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2 years ago

Find the value of two numbers if their sum is 21 and their difference is 5

Mathematics

1 answer:

kykrilka [37]2 years ago

6 0

Answer: x = 13 and y = 8

Step-by-step explanation:

Two numbers must add to 21. We don't know them yet, so let's just use a placeholder for both of them for now.

x + y = 21

Their difference is five, meaning that if we subtract one from the other, we get five. Again, we don't know the numbers yet, so we'll add a placeholder for now.

x - y = 5

We can now solve a system of equations for x.

x = y + 5

y + 5 + y = 21

2y + 5 = 21

2y = 16

y = 8

x - 8 = 5

x = 13

So x = 13 and y = 8

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Which statement is correct?

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Answer:

$2.06 \times 10^-^2 = 206$

$1.88 \times 10^-^1 = 18.8$

$206 \times 18.8 = 3,872.8$

$7.69 \times 10^-^2 = 769$

$2.3 \times 10^-^5 = 230,000$

$=\frac{769}{230000}$

= 0.00334

therefore,

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Step-by-step explanation:

Which statement is correct?

(2.06x102x1.88 x 10-1) <7.69x 10

2.3x10-5

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2.3x10-5

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Given that;

$2.06 \times 10^-^2 = 206$

$1.88 \times 10^-^1 = 18.8$

$206 \times 18.8 = 3,872.8$

$7.69 \times 10^-^2 = 769$

$2.3 \times 10^-^5 = 230,000$

$=\frac{769}{230000}$

= 0.00334

therefore,

3,872.80 > 0.00334

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