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xz_007 [3.2K]
3 years ago
13

At a certain restaurant, milkshakes cost $4 and cheeseburgers cost $6. If Al buys 1 milkshake and x cheeseburgers and spends at

least $30 but no more than $46,
what is one value of x
Mathematics
1 answer:
Katena32 [7]3 years ago
5 0

Answer:

5, 6 or 7

Step-by-step explanation:

If Al spends $30, the number of cheeseburgers bought is:

x=\frac{30-4}{6}\\x=4.3333

Since $30 is the minimum value, he has to buy at least 5 cheeseburgers.

If Al spends $46, the number of cheeseburgers bought is:

x=\frac{46-4}{6}\\x=7

Therefore, Al bought between 5 and 7 cheeseburgers, which means that 5, 6 or 7 are possible values of x.

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Korolek [52]

Answer:

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Step-by-step explanation:

First, set up a system of equations:

Let x = number of children and y = number of adults

There is a total of 16 people, so x+y = 16. This is your first equation.

Each child ticket costs $6, so 6x = cost of children's tickets based on the number of children present (x)

Each adult ticket costs $9, so 9y = cost of adult's tickets based on the number of adults present (y)

The total cost of tickets is $129, so 6x+9y = 129. This is your second equation.

Your system of equations is now this:

 x +   y = 16

6x + 9y = 129

You can solve this system using the method of elimination, where we will eliminate the variable x (number of children), since we are focused on y (number of adults).

Multiply the top equation by -6. This will give the following equation:

-6x - 6y = -96

You can now solve the system of equations by placing the new equation under the second equation like this:

6x + 9y = 129

-6x - 6y = -96

Now, add the two equations together.

6x + (-6x) = 0

9y + (-6y) = 3y

129 + (-96) = 33

After doing this, you get the following equation:

3y = 33

As you can see, the variable x has been eliminated, and you are left with y.

Solve the equation for y:

3y = 33

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Answer:

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