The length of the bedroom exists at x = 9 and y = 6.
<h3>How to estimate the length of the bedroom?</h3>
From the given information, we get
Then 
Solve this for x.
simplifying the value of x we get
Equate (1/9) to 1/x.
x = 9 (feet).
Convert 1.5 inches to feet using a proportion:
Solve this for y.
simplifying the value of y we get
(1/4)y = 3/2
Multiply both sides of the equation by 4.
y = 6
Therefore, the length of the bedroom exists at x = 9 and y = 6.
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The statement best describes Cheryl's computer is option C. Cheryl accelerated to 65 mph, drove at a constant speed for 5.5 minutes, and then decelerated to 45 mph.
<h3>How to find the function which was used to make graph?</h3>
A graph contains data of which input maps to which output.
Analysis of this leads to the relations which were used to make it.
If we know that the function crosses the x-axis at some point, then for some polynomial functions, we have those as roots of the polynomial.
Let's assume the graph of Cheryl's commute was like the one below.
We can see that she started at 0 mph.
One minute later, she was up to 65 mph, so she had accelerated (increased her speed).
At 6.5 min (5.5 min later) her speed was still 65 mph therefore, she was driving at a constant speed.
Over the next 2.5 min, her speed dropped to 45 mph, therefore she was decelerating.
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Answer:
If you were solving the right triangle, it would be:
m∠A = 46°
m∠B = 44°
m∠C = 90°
AB = 32
BC ≈ 23
AC ≈ 24
Step-by-step explanation:
To solve this right triangle, you can use trigonometric ratios to solve for the sides. To find the angle measures:
m∠A = 46° (given)
m∠B = x
m∠C = 90° (given)
180 - (46 + 90) = x
180 - 136 = x
44 = x
m∠B = 44°
To find the side measures, you can use tangent, sine, cosine, and the Pythagorean Theorem.
Recall that:
tangent = opposite side/adjacent side
sine = opposite side/hypotenuse
cosine = adjacent side/hypotenuse
So:
sin46 = BC/32
BC = 32 (sin46)
BC ≈ 23
tan46 = BC/AC
AC = BC/tan46
AC = (23.01887361...) (tan46)
AC ≈ 24
Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
