Which transformation is not always congruent with its original image?

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

8 0

The answer is A.... dilation

user100 [1]3 years ago

6 0

A) dilation, because size is changed by a factor/ratio

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Elmer has a collection of 300 fossils. Of these, 21 percent are fossilized snail shells.

chubhunter [2.5K]

In order to figure out the number of fossilized snail shell, multiply 21% by 300. first change 21% into a decimal, in order to do that, move the percent symbol two spaces to the left, and replace the "%" symbol to a decimal. 0.21 X 300= 63
so 21% of 300 is 63

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3 years ago

What's the rate for a 2,500 principle and a interest of 750 and time 3 years

tekilochka [14]

9.14% is the number rounded to the nearest hundredth

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Recently, More Money 4U offered an annuity that pays 5.7 % compounded monthly. If $1,011 is deposited into this annuity every

Tresset [83]

Recall that the future value (FV), of an annuity payment of $P, for, n years at, t times a year at, r% interest compounded, t times a year is given by
$FV=P \frac{\left(1+ \frac{r}{t} \right)^{nt}-1}{\frac{r}{t}}$

Given that More Money 4U offered an annuity that pays r = 5.7% = 0.057 compounded monthly (12 times a year or t = 12). If P = $1,011 is deposited into this annuity every month (t = 12), then after n = 6 years the amount in the account is given by:
$FV=1,011\times \frac{\left(1+ \frac{0.057}{12} \right)^{6\times12}-1}{\frac{0.057}{12}} \\ \\ =1,011\times \frac{(1+0.00475)^{72}-1}{0.00475} =1,011\times \frac{(1.00475)^{72}-1}{0.00475} \\ \\ =1,011\times \frac{1.406621-1}{0.00475} =1,011\times \frac{0.406621}{0.00475} =1,011\times85.6044 \\ \\ =\$86,546.05$

Therefore, the amount in the account after 6years rounded to the nearest dollar is $86,546.

PART 2:
Given that $1,011 is deposited into this annuity every month for 6 years, the amount deposited into the account is given by
$1,011 x 12 x 6 = $72,792

Therefore, the amount of interest accrued is given by
$86,546 - $72,792 = $13,754

Therefore, the amount of interest received is $13,754

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3 years ago

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Semenov [28]

Reflecting across the x axis changes the polarity of the y coordinate so the answer would be x

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3 years ago

Find the dimension of the subspace of all vectors in set of real numbers r superscript 4ℝ4 whose firstfirst and thirdthird entri

Oduvanchick [21]

The subspace has dimension 3.

Intuitively, you can think that you're removing one degree of freedom from $\mathbb{R}^4$ . In fact, this space is generated by the following span:

$\lambda_1 (1,0,0,0) + \lambda_2 (0,1,0,0) + \lambda_3 (0,0,1,0) + \lambda_4 (0,0,0,1)$

Since the first and third coordinate must be the same, we have $\lambda_1 = \lambda_3$ . So, the span becomes

$\lambda_1 (1,0,0,0) + \lambda_2 (0,1,0,0) + \lambda_1 (0,0,1,0) + \lambda_4 (0,0,0,1)$

which is the same as

$\lambda_1 (1,0,1,0) + \lambda_2 (0,1,0,0) + \lambda_4 (0,0,0,1)$

And so you can see that the space is generated by three vectors.

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4 years ago