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seropon [69]
4 years ago
8

6+4E-6V=3 solve for E

Mathematics
1 answer:
notka56 [123]4 years ago
6 0

Answer:

             \bold{E\ =\ \dfrac{6V-3}4=\dfrac32V-\dfrac34}

Step-by-step explanation:

\bold{6+4E-6V\ =\ 3}\\\\{}\ \ -6+6V\qquad -6+6V\\\\\bold{4E\ =\ 3-6+6V}\\\\\bold{4E\ =\ 6V-3}\\\\\div4\quad\ \div4\\\\\bold{E\ =\ \frac{6V-3}4=\frac32V-\frac34}

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s=(1440Aπd)/(360πd^2)

s=4A/d and since A=10mi^2 and d=20mi

s=(4*10)/20

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3 years ago
Compare the graphs of y = |x + 2| and y = -|x + 1|. Which statement is true? a.The value of coefficient a is +1 in both equation
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3 years ago
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