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Mnenie [13.5K]
4 years ago
10

The Bradenton Post polled 1,356 adults in the city to determine whether they wet their toothbrush before they put toothpaste on

it. Of the respondents, 54% said they wet it first. Suppose 68% of all adults actually wet their toothbrush first. What are the mean and standard deviation of the sampling distribution?
The mean is 0.54 and the standard deviation is 0.0135.
The mean is 0.54 and the standard deviation is 0.0127.
The mean is 0.68 and the standard deviation is 0.0224.
The mean is 0.68 and the standard deviation is 0.0135.
The mean is 0.68 and the standard deviation is 0.0127.
Mathematics
1 answer:
natulia [17]4 years ago
4 0

Answer:

The mean is 0.54 and the standard deviation is 0.0135.

Step-by-step explanation:

i) the mean of the sampling distribution is 0.54

ii) the mean for the sampling distribution, p = 0.54

iii) therefore for the sampling distribution, q = ( 1 - 0.54) = 0.46

iv) the sample size of the distribution, n = 1356

v)  the\hspace{0.1cm} standard\hspace{0.1cm}  deviation\hspace{0.1cm}  s = \sqrt{\frac{p\times q}{n} }  = \sqrt{\frac{0.54\times 0.46}{1356} } = 0.0135

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Rewrite in simplest terms: (9x+5)-(-2x+10)(9x+5)−(−2x+10)
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\implies {\blue {\boxed {\boxed {\purple {\sf {  18 {x}^{2}  - 69x - 55}}}}}}

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<h3>\boxed{    Note:}</h3>

\sf\pink{PEMDAS\: rule.}

P = Parentheses

E = Exponents

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Here hope this helps best of luck :)




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