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Lunna [17]
3 years ago
14

I need the answers please

Mathematics
2 answers:
AleksandrR [38]3 years ago
4 0
NUMBER 1
Subtitute y with x to find the value of x
y = -x + 2
x = -x + 2
x + x = 2
2x = 2
x = 2/2
x = 1

Subtitute x with 1 to find the value of y
y = x
y = 1

Solution
(x,y) = (1,1)


NUMBER 2

Subtitute y with x + 4 to find the value of x
y = 3x
x + 4 = 3x
x - 3x = -4
-2x = -4
x = -4/-2
x = 2

Subtitute x with 2 to find the value of y
y = 3x
y = 3(2)
y = 6

Solution
(x,y) = (2,6)


NUMBER 3

Subtitute x with y-5 to find the value of y
x = -2y + 1
y - 5 = -2y + 1
y + 2y = 1 + 5
3y = 6
y = 6/3
y = 2

Subtitute y with 2 to find the value of x
x = y - 5
x = 2 - 5
x = -3

Solution
(x,y) = (-3,2)


NUMBER 4
Subtitute x with y + 50 to find the value of y
x + 2y = 200
y + 50 + 2y = 200
3y = 200 - 50
3y = 150
y = 150/3
y = 50

Subtitute y with 50 to find the value of x
x = y + 50
x = 50 + 50
x = 100

Solution
(x,y) = (100,50)
KatRina [158]3 years ago
3 0
Just answers?
1. y=1, x=1
2. y=6, x=2
3. y=2, x=-3
4. y=50, x=100
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The temperature on a winter day increased 37oF. If the beginning temperature was -9oF, what was the temperature after the increa
Rashid [163]
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the beginning temperature: -9
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ankoles [38]

Answer:

As few as just over 345 minutes (23×15) or as many as just under 375 minutes (25×15).

Imagine a simpler problem: the bell has rung just two times since Ms. Johnson went into her office. How long has Ms. Johnson been in her office? It could be almost as short as just 15 minutes (1×15), if Ms. Johnson went into her office just before the bell rang the first time, and the bell has just rung again for the second time.

Or it could be almost as long as 45 minutes (3×15), if Ms. Johnson went into her office just after the bells rang, and then 15 minutes later the bells rang for the first time, and then 15 minutes after that the bells rang for the second time, and now it’s been 15 minutes after that.

So if the bells have run two times since Ms. Johnson went into her office, she could have been there between 15 minutes and 45 minutes. The same logic applies to the case where the bells have rung 24 times—it could have been any duration between 345 and 375 minutes since the moment we started paying attention to the bells!

Step-by-step explanation:

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Answer:

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Suppose the owner of a local apple orchard has 4 half-bushels of apples to sell. He loads them on his truck, and drives his rout
NikAS [45]

Answer:

a) The orchard owner's expected profit from driving the route is $33.

b) The standard deviation of the profit is $27.28

Step-by-step explanation:

a) Data and Calculations:

Apples to sell = 4 half-bushels

Price of each half-bushel sold = $40

Sales revenue = $160 ($40 *4)

Cost of driving the route = $15

Expected values:

Event                          Probability  Revenue       Profit         Expected  Profit

No Sales                        40%            $0         ($15) ($0 - $15)        ($6.00)

Selling 1 half-bushel      30%         $40         $25 ($40 - $15)         $7.50

Selling 2 half-bushels   10%          $80         $65 ($80 - $15)        $6.50

Selling 3 half-bushels   10%         $120       $105 ($120 - $15)     $10.50

Selling 4 half-bushels   10%         $160       $145 ($160 - $15)     $14.50

Total expected profit = $33

Event                          Expected  Profit  Mean        Squared

                                                                       Difference

No Sales                            ($6.00)        -39             1,521

Selling 1 half-bushel           $7.50         -25.5           650.25

Selling 2 half-bushels        $6.50         -26.5           702.25

Selling 3 half-bushels      $10.50         -22.50         506.25

Selling 4 half-bushels      $14.50         -18.50          342.25

Sum of squared differences                                     3,722

Mean of squared differences = 744.4 (3,722/5)

Standard deviation = square root of the mean

= 27.28

= $27.28

3 0
3 years ago
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