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taurus [48]
3 years ago
10

Evaluate the expression. -2(12 – 2(-4))? What is the value of the expression

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
5 0

Answer:

-40

Step-by-step explanation:

-4 * 2 = -8

-8*-1= 8

12+8 = 20

20*(-2) =-40

Masteriza [31]3 years ago
3 0

Answer:

The answer is -40.

Step-by-step explanation:

Use PEMDAS and the distributive property.

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
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Divide 5 3/4 ÷ 1 1/2
Kipish [7]

The required mixed number is 3\frac{5}{6} . The calculations are attached with the solution as an image.

What is a mixed number ?

  • A bit represented with its quotient and remainder is a mixed bit. For illustration,21/3 is a mixed bit, where 2 is the quotient, 1 is the remainder.
  • So, a mixed bit is a combination of a whole number and a proper bit. A mixed bit, also called a mixed number, is a whole number and a bit together.
  • The bit is written to the right of the whole number.
  • A mixed number is formed by combining three corridor a whole number, a numerator, and a denominator. The numerator and denominator are part of the proper bit that makes the mixed number.

The required mixed number is 3\frac{5}{6} . The calculations are attached with the solution as an image.

Learn more about mixed number here:

brainly.com/question/1746829

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6 0
1 year ago
Which number line correctly graphs the numbers in the list?​
Oksana_A [137]

Answer:

the first option

Step-by-step explanation:

8 0
2 years ago
. Write a word problem that can be acted out using these counters.
Rufina [12.5K]
Please comment on this answer and give me a full question and I will be just fine answering it for you.
8 0
3 years ago
Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)
DENIUS [597]

Compute the necessary values/derivatives of f(x) at x=1:

f(1)=3

f'(1)=2

f''(1)=-12

f'''(1)=-12

f^{(4)}(1)=48

f^{(5)}(1)=120

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) f(x) at x=1 by

T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5

T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5

###

Another way of doing this would be to solve for the coefficients a,b,c,d,e,g in

f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5

by expanding the right hand side and matching up terms with the same power of x.

5 0
3 years ago
Plzzz help i will give brainliest if i can
Alla [95]

Answers: choice C and choice E

Plugging x = 3 and y = -1 into both equations of choice C lead to a true result (the same number on both sides). This is why the system of equations listed in choice C is one possible answer. Choice E is a similar story.

If your teacher didn't mean to make this a "select all that apply" type of problem, then it's likely your teacher may have made a typo.

3 0
3 years ago
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