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Snowcat [4.5K]
3 years ago
6

A church rings its bells every 15 minutes, the school rings its bells every 20 minutes and the day care center rings its bells e

very 25 minutes. If they all ring their bells at noon on the same day, at what time will they next all ring their bells together
Mathematics
1 answer:
ankoles [38]3 years ago
7 0

Answer:

As few as just over 345 minutes (23×15) or as many as just under 375 minutes (25×15).

Imagine a simpler problem: the bell has rung just two times since Ms. Johnson went into her office. How long has Ms. Johnson been in her office? It could be almost as short as just 15 minutes (1×15), if Ms. Johnson went into her office just before the bell rang the first time, and the bell has just rung again for the second time.

Or it could be almost as long as 45 minutes (3×15), if Ms. Johnson went into her office just after the bells rang, and then 15 minutes later the bells rang for the first time, and then 15 minutes after that the bells rang for the second time, and now it’s been 15 minutes after that.

So if the bells have run two times since Ms. Johnson went into her office, she could have been there between 15 minutes and 45 minutes. The same logic applies to the case where the bells have rung 24 times—it could have been any duration between 345 and 375 minutes since the moment we started paying attention to the bells!

Step-by-step explanation:

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To solve this problem, all we need is the conversion factor.

We know that there are:

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4 years ago
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To answer this, you would use the original ratio of 2 to 5 and create an equivalent ratio that includes the 12 tulips. You would get a ratio of 12 to 30. This is not enough daisies.

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4 years ago
A fruit company sells two types of boxes large and small. A delivery of two large boxes and three small boxes has a total weight
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Answer:

the large box weight is 6.50 kg and the small box weight is 13.75 kg

Step-by-step explanation:

The computation of each type of box weight is as follows:

Let us assume the large box be x

And, the small box be y

So,

2x + 3y = 47.......(i)

6x + 5y = 115........(ii)

Multiply by 3 in equation 1

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6x + 5y = 115

Now subtract the last equation from the above one

4y = 26

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For x, it would be

2x+ 3(6.50) = 47

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2x = 47 - 19.50

2x = 27.50

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Hence, the large box weight is 6.50 kg and the small box weight is 13.75 kg

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Answer:

I would go with c.

Step-by-step explanation:

Hope this helped!

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