Answer:
<em>communications</em><em>,</em><em>risk</em><em>,</em><em>systems</em><em>,</em><em>test</em><em>ins</em><em>,</em><em>procedures</em><em>,</em><em>interviews</em><em>,</em><em>documents</em><em>.</em>
Explanation:
The auditor considers many factors in determining the nature, timing, and extent of auditing procedures to be performed in an audit of an entity's financial statements. One of the factors is the existence of an internal audit function. fn 1 This section provides the auditor with guidance on considering the work of internal auditors and on using internal auditors to provide direct assistance to the auditor in an audit performed in accordance with generally accepted auditing standards.Note: When performing an integrated audit of financial statements and internal control over financial reporting, refer to paragraphs 16-19 of PCAOB Auditing Standard No. 5, An Audit of Internal Control Over Financial Reporting That Is Integrated with An Audit of Financial Statements, for discussion on using the work of others to alter the nature, timing, and extent of the work that otherwise would have been performed to test controls.
Roles of the Auditor and the Internal Auditors
<em>02 </em>
<h2>
<em>I</em><em> </em><em>HOPE</em><em> </em><em>THIS</em><em> </em><em>HELPS</em><em> </em><em>ALOT</em><em>!</em><em> </em><em>:</em><em>3</em></h2>
Search for it in the start menu. Once you find it, right click and press "Pin to taskbar."
9 is the correct answer. 4*2=8 loops are executed, moving the count from 1 to 9.
Solution:
The flagging of an uncommon last name as a spelling error can be stopped by opening the shortcut menu on the first occurrence of the name and selecting of ignoring all.
Thus the required right answer is B.
Answer:
If all the character pairs match after processing both strings, one string in stack and the other in queue, then this means one string is the reverse of the other.
Explanation:
Lets take an example of two strings abc and cba which are reverse of each other.
string1 = abc
string2 = cba
Now push the characters of string1 in stack. Stack is a LIFO (last in first out) data structure which means the character pushed in the last in stack is popped first.
Push abc each character on a stack in the following order.
c
b
a
Now add each character of string2 in queue. Queue is a FIFO (first in first out) data structure which means the character inserted first is removed first.
Insert cba each character on a stack in the following order.
a b c
First c is added to queue then b and then a.
Now lets pop one character from the stack and remove one character from queue and compare each pair of characters of both the strings to each other.
First from stack c is popped as per LIFO and c is removed from queue as per FIFO. Then these two characters are compared. They both match
c=c. Next b is popped from stack and b is removed from queue and these characters match too. At the end a is popped from the stack and a is removed from queue and they both are compared. They too match which shows that string1 and string2 which are reverse of each other are matched.