3k^3 should be the answer.
A financial analyst wanted to estimate the mean annual return on mutual funds. A random sample of 60 funds' returns shows an average rate of 12%. If the population standard deviation is assumed to be 4%, the 95% confidence interval estimate for the annual return on all mutual funds is
A. 0.037773 to 0.202227
B. 3.7773% to 20.2227%
C. 59.98786% to 61.01214%
D. 51.7773% to 68.2227%
E. 10.988% to 13.012%
Answer: E. 10.988% to 13.012%
Step-by-step explanation:
Given;
Mean x= 12%
Standard deviation r = 4%
Number of samples tested n = 60
Confidence interval is 95%
Z' = t(0.025)= 1.96
Confidence interval = x +/- Z'(r/√n)
= 12% +/- 1.96(4%/√60)
= 12% +/- 0.01214%
Confidence interval= (10.988% to 13.012%)
Use the compound interest formula: A=P(1+i)^t.
P is the initial amount of the drug, 0.3ml.
i is - 0.0035.
t is in seconds.
You'll get:
A=0.3(1-0.0035)^t.
Sub in any value on t to find out how many ml are left t seconds after injection.
The 0.65 second injection time does not seem to be relevant as the question clearly states that the exponential decay starts AFTER the injection is completed.
D.36 60 .... because 6 times 6 is 36 and 6 times 10 is 60
Step-by-step explanation:
Enter the following numbers in the boxes provided sequentially.
First box : 7
Second box: 2
Third box: 3
Fourth box : 4
Fifth box: 8
Sixth box: 3
