First, let's review the formula for the "sum of two cubes:"
a^3 + b^3 = (a + b)(a^2 - ab + b^2).
Unfortunately, 9 is not a perfect cube. The cube root of 9 is 9^(1/3), and the square of the cube root of 9 is therefore 9^(2/3).
Thus,
9x^3 + 64 = (9^(1/3)*x + 4) * (9^(2/3)x^2 - 4*9^(1/3) + 16)
Answer:y=0.5x-10.5
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
The whole goal is to isolate the variable.
3x-1=8
1+3x-1=8+1 first add 1 to both sides of the equation to cancel out the -1
3x=9 now just divide 3 to both sides of the equation because the opposite of multiplication is division. So dividing 3 on both sides cancels out the 3 to isolate the x
3x/3=9/3
x=3
You need to find out if 57 can be divided evenly by a number other than 1 and 57.
57 is odd, so it is not divisible by 2.
The digits of 57 are 5 and 7. Add 5 + 7 to get 12. Since 12 is divisible by 3 (12/3 = 4), then 57 is also divisible by 3.
57/3 = 19
19 is a prime number, so the only factors of 57 are 1, 3, 19, 57.
57 rows can be divided into 19 sections of 3 rows each or 3 sections of 19 rows each.
