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3 years ago

If f(x) = 7x+2, find f (0)

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

4 0

Answer:

f (0) = 2

Step-by-step explanation:

f (x) = 7x + 2

f (0) = 7 × 0 + 2

= 2

quester [9]3 years ago

3 0

Answer:

f(0) = 2

Step-by-step explanation:

f(x) = 7x+2

→ f(0)

f(0) = 7(0)+2

= 0+2

= 2

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Does anyone know how to factor y^2+49?

Delvig [45]

Answer:

(y + 7i)(y - 7i)

Step-by-step explanation:

It cannot be factored using real numbers, but consider

7i × - 7i

= -49i² and i² = - 1

= 49

The factoring as a difference of squares to obtain

y² + 49 = (y + 7i)(y - 7i)

5 0

3 years ago

Read 2 more answers

What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)

lbvjy [14]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}$

$BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}$

$DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89$

8 0

2 years ago

Ryker is given the graph of the function y= 1/2x^2 - 4 . He wants to find the zeros of the function but is unable to read them e

REY [17]

$y = \frac{1}{2x^{2} - 4}$
$0 = \frac{1}{2x^{2} - 4}$
$0(2x^{2} - 4) = (2x - 4)(\frac{1}{2x^{2} - 4})$
$0(2x^{2}) - 0(4) = 1$
$0 - 0 = 1$
$0\neq1$

8 0

3 years ago

Graph the inequality;y>-5x+3

Evgesh-ka [11]

Start your dot on 3 on the y axis. Move is downwards on the y axis by 5 everytime you move over once on the x axis. Shade all the stuff above the line since it says y is greater than -5x+3

7 0

3 years ago

If m, p, and t are distinct positive prime numbers, then (m^3)(p)(t) has how many different positive factors greater than 1?

harina [27]

Answer:

d. 15

Step-by-step explanation:

List the exponents of each of the prime factors. Here, they are 3, 1, 1.

Add 1 to each of these values and form the product of these sums:

(4)(2)(2) = 16

This is the number of divisors of the number. Since 1 is included in this count, 15 of the divisors are greater than 1.

3 0

3 years ago

If f(x) = 7x+2, find f (0)​

If f(x) = 7x+2, find f (0)