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bekas [8.4K]
3 years ago
6

The graph shows the wolf population in

Mathematics
1 answer:
nordsb [41]3 years ago
4 0

Answer:

I think D but im not sure

Step-by-step explanation:

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Sarah wants to paint three walls in her family room. Two walls are 18 feet long by 10 feet
Brrunno [24]

Answer:

The total area is 444 ft².

Step-by-step explanation:

First you multiply 18 by 10 for one of the walls you get 180*2 since you have two walls with the same dimension. Next you do 12*7 to get 84. Last you would add 84 to 360 and get 444 ft²

8 0
3 years ago
Please solve (Write which letter the answer is please )
Vinvika [58]

Answer:

B

Step-by-step explanation:

One side has an area of 2, one has an area of 1, and one has an area of 8. You count each of these twice.

8 0
4 years ago
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A manufacturing plant earned $80 per man hour of labor when it opened Each year, the plant carns an
galina1969 [7]

Answer: 16

Step-by-step explanation:

80 divided by 5 equals 16

6 0
3 years ago
15% of 95? and 3 1/2% of 100?
NISA [10]

Answer:

15% of 95-14.25

3 1/2% of 100-3.5

Step-by-step explanation:

3 0
3 years ago
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Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
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