I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
Answer:
The right answer for the question that is being asked and shown above is that: "d. P(A and B) = x + y." The probability of event A is x, and the probability of event B is y. If the two events are independent, the condition must be true is this d. P(A and B) = x + y
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Step-by-step explanation:
Answer:
it is 69
Step-by-step explanation:
do calculations
Answer:
1560
Step-by-step explanation:
The rate of Increase of the population (P) of the bacteria is given as:
Where k is a constant of Integration.
At t=0, P(t)=36
Therefore:
Answer:
(9b + 3c + 10d)cm
Step-by-step explanation:
Given the sides of a triangle expressed as (2b+c), (7b + 4d) and (6d+2c). The perimeter of the triangle is the sum of all the sides of the triangles.
Perimeter of the triangle = 2b+c + 7b+4d + 6d+2c
Perimeter of the triangle = 2b + 7b + c + 2c + 4d + 6d
Perimeter of the triangle = 9b + 3c + 10d
Hence the perimeter of the triangle is (9b + 3c + 10d)cm
