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yarga [219]
3 years ago
11

Change this improper fraction into a mixed number: 89/9

Mathematics
2 answers:
enyata [817]3 years ago
8 0
1) 11 1/8

2) 5/7

3)it would be 233/3 but since that isn't your option try going with 23/3

4) 10 / 16

5) 9/3 = 3 (aka 3/1 ) then 3/9 = 0.3.
Answer for number 5 ⬇
Therefore 9/3 would be your greatest
~the fractions doesn't equal each other~{meaning that the equal sign wouldn't be your answer} ~
~3/9 Would be lesser than 9/3~
~just make the fraction into division .it might help ~
~~~~~~~~~~~~~`~~~~~~~~~~~~~~~~~~~~~~~~~~~
For improper fraction just multiply and add
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Looking for the equivalent of the fractions... try dividing as well
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Example of a improper fraction

Problem : 12 3/5

Work: 12(5) = 60
60 +( 3 )= 63
Answer : 63/ 5
(note: don't worry about the example .... its not apart of the questions you asked.. but you can if you want to ... don't get me wrong.. if it was helpful you can use it )

☺
Katyanochek1 [597]3 years ago
3 0
1. 89/9 = 9 8/9
2. 40/56 = 5/7
3. 77 2/3 = 23/3
4. 5/8 = 10/16
5. 3/9 _ 9/3 = 3/9 < 27/9
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The height (feet) of an object moving vertically is given by s= (-16t^2)+(208t)+(156), where t is in seconds.
OverLord2011 [107]

Answer:

The object's velocity at t = 7 is -16 ft/s

The maximum height is 832 ft and it occurs when t=\frac{13}{2}

Step-by-step explanation:

From the information given, the equation of motion of the object is

s(t)= -16t^2+208t+156

For any equation of motion s(t), the instantaneous velocity at time t is given by

v(t)=\frac{ds}{dt}

(a) To find the object's velocity at t = 7, you must:

v(t)=\frac{d}{dt}(-16t^2+208t+156)\\\\v(t)=-\frac{d}{dt}\left(16t^2\right)+\frac{d}{dt}\left(208t\right)+\frac{d}{dt}\left(156\right)\\\\v(t)=-32t+208+0\\\\v(t)=-32t+208

Next, we evaluate when t = 7

v(7)=-32(7)+208=-224+208\\\\v(7)=-16

The object's velocity at t = 7 is -16 ft/s

(b) <em>To find the maximum of a function we always use the derivative of the function and we set it equal zero to find the</em><em> critical points.</em>

To find the maximum height and when it occurs, we set the velocity function equal to 0 and solve for t.

-32t+208=0\\\\-32t+208-208=0-208\\\\-32t=-208\\\\\frac{-32t}{-32}=\frac{-208}{-32}\\\\t=\frac{13}{2}

Next, we substitute this value into the equation of motion to find the maximum height

s(\frac{13}{2})= -16(\frac{13}{2})^2+208(\frac{13}{2})+156\\\\s(\frac{13}{2})=-676+1352+156)=832

The maximum height is 832 ft and it occurs when t=\frac{13}{2}

6 0
4 years ago
‼️PLEASE HELP‼️‼️ Juan has $13 dollars in his piggy bank. Each week on Monday, he gets $10 for his allowance . Write a function
Semmy [17]

Answer:

f(x) = 10x + 13

Function f(7) = 83

Step-by-step explanation:

y = 10x + 13

f(x) = 10x + 13

Function f(7) = 10(7) + 13

Function f(7) = 83

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3 years ago
Ben is 18 years old. He decided to start investing $180 every month into an average mutual fund (interest rate 12%). How much mo
irina [24]

Answer:

$1,762,932.78

Step-by-step explanation:

180 per month at 12% apr for 40 years.

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Un número multiplicado que me 343
irina1246 [14]
7 multiplicado por 49 =343
6 0
3 years ago
I really need help been on this problem for like 20 min
ycow [4]
Start with x:
Since x and 57º make a straight line, x+57 = 180 (because a line is 180º). This says x=123º

Now for y:
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