Answer:
Observe that f(x) is a continuous function when 
because is a polynomial. The possible problem may occur in x=1.
Then, f(x) is discontinuous in x=1 if the limits of f to the right and the left of 1 exist and are different or if some of those limits doesn't exist.
Let's calculate the limits:
Since, 
then f(x) is discontinuous in x=1.
You have:
1)The slant height is:
Slant height=√[(8 inches)²+(8 inches)²]
Slant height=10 inches
2)The lateral area is:
LA=(Perimeter)(Slant height)/2
LA=(6 inches)(4)(10 inches)/2
LA=120 inches²
3)The Surface area is:
SA=Base area+(PerimeterxSlant height/2)
SA=(6 inches)²+(24 inchesx10 inches/2)
SA=156 inches²
4)The volume is:
V=(6 inches)²(8 inches/3)
V=96 inches³
In this question, Suzan is taking 5 marble from a bag containing 4 red marbles, 3 green ones, 4 white ones, and 3 purple ones. The total marble in the bag should be: 4+3+4+3= 14. The question is how much the probability to get <span>1 red, 2 green, 1 white and 1 purple.
Ways to take 5 marble out of 14=14C5= 14!/5!9!= </span>2002<span>
</span>Ways to take 1 red marble out of 4= 4C1= 4<span>
</span>Ways to take 2 green marble out of 3= 3C2= 3
Ways to take 1 white marble out of 4= 4C1= 4
Ways to take 1 purple marble out of 3= 3C1= 3
Then the probability would be: 4*3*4*3/ 2002= 144/2002= 72/1001
Answer:
(0.6613, 8.3387)
Step-by-step explanation:
Let the heights of men be the first population and the heights of women be the second population. Then
We have 
, 
, 
and
, 
, 
. The pooled
estimate is given by
The 99% confidence interval for the true mean difference between the mean height of the men and the mean height of the women is given by (if the samples are independent)
, i.e.,
where 
is the 0.5th quantile of the t distribution with (15+7-2) = 20 degrees of freedom. So
, i.e.,
(0.6613, 8.3387)
Answer:
Sorry, I'm late but it's 
Hope this helps :D
Step-by-step explanation:
I took the test
