Because you are using the format y = mx +c the c value is the y offset.
in this equation the equation can be rewritten as y = 1x -3
Thus the y intercept, the y offset, must be -3.
Hope this helps! :)
The simplest way to solve this is to notice that letting t = 8/3 will let the term (3t-8) = 0. Substituting this will make v(t) = 2. Then we check which graphs pass through (8/3, 2). Only the second and third graphs do.
Next, we look at the behavior of the graph as t increases. Based on the equation, as t increases, (3t-8)^3 increases as well, so v(t) will increase as well. This is shown by the second graph, in which v(t) increases as t increases.
112=2∗56, I believe would be the answer to your question. (<span>The Prime Factors of 112: </span><span>2^4 • 7)</span>
Answer:
A, b, c, y are linear becouse every value of domain has one value in range
Step-by-step explanation:
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Answer:
True
Step-by-step explanation:
True, a problem is ill-conditioned if its solution is highly sensitive to small changes in the problem data.
However, higher-precision arithmetic will make an ill-conditioned problem better conditioned.
In an ill-conditioned problem, for a small change in the independent variable, there is a large change in the dependent variable.
