Qn. 1
Lower bound for Zoe's weight = 62 - (1/2) = 62 - 0.5 = 61.5 kg
Qn. 2
Upper bound for length AB = 8.3+ (0.1/2) = 8.3+0.05 = 8.35 cm
Qn. 3
Upper bound for Anu's wight = 83+(0.5/2) = 83+0.25 = 83.25 kg
Qn. 4
Lower bound for length CD = 27-(0.5/2) = 27-0.25 = 26.75 cm
Qn. 5
Upper bound for sides of the hexagon = 3.6+(0.1/2) = 3.6+0.05 = 3.65 cm
Upper bound for the perimeter = upper bound for the sides*6 = 3.65*6 = 21.9 cm
Qn. 6
Perimeter = 4*length => side = Perimeter/4 = 24/4 = 6
Bound = 0.5/4 = 0.125
Lower bound of the length = 6-0.125 = 5.875 cm
Qn. 7
For the area,
Upper bound = 80+(10/2) 80+5 = 85 cm^2
For the length
Upper bound = 12+(1/2) = 12+0.5 = 12.5
Then, upper bound for the width = Upper bound for the area/upper bound for the length = 85/12.5 = 6.8 cm
Qn. 8
Lower bound for the area = 230-(1/2) = 230-0.5 = 229.5 cm^2
Lower bound for the sides of the square = Sqrt(Lower bound of the area) = Sqrt (229.5) = 15.15
Then,
Lower bound of perimeter = 4(Length) = 4*15.15 = 60.6 cm
Answer:
C. 31.83 feet.
Step-by-step explanation:
We have been given that Trina has $1000 to purchase an open-top cylindrical dog pen in her backyard. She wants the height of the pen to be 5 feet.
First of all, we will find the surface area of dog pen using surface area of cylinder.
,where,
r = Radius of cylinder,
h = Height of cylinder.
Since the area of each square foot of pen costs $1, so in $1000 Trina can cover an area of 1000 square feet.
Now, we will set the surface area of cylinder equal to 1000 to solve for the radius.
Upon dividing both sides of our equation by 10 pi we will get,
Therefore, the radius of the dog pen is 31.83 feet and option C is the correct choice.
For part A: two transformations will be used. First we will translate ABCD down 3 units: or the notation version for all (x,y) → (x, y - 3) so our new coordinates of ABCD will be:
A(-4,1)
B(-2,-1)
C(-2,-4)
D(-4,-2)
The second transformation will be to reflect across the 'y' axis. Or, the specific notation would be: for all (x,y) → (-x, y) New coordinates for A'B'C'D'
A'(4,1)
B'(2,-1)
C'(2,-4)
D'(4,-2)
Part B: The two figures are congruent.. We can see this a couple of different ways.
- first after performing the two transformations above, you will see that the original figure perfectly fits on top of the image.. exactly the same shape and size.
- alternatively, you can see that the original and image are both parallelograms with the same dimensions.
Multiple each number I think
Hello!
Judging on the questions you have provided I have come to the conclusion that to solve all of these you need to find the value of x by isolating it all on one side and simplifying.
For question #1 the first step would be to subtract 6 from each side.
The outcome should be -x=-6-12, and if simplified -x=-18.
Next, you want to divide each side by -1 because x needs to always be positive when finding the solution.
Your answer for #1 should be X=18, D.
For question #2 the first step you should take is to subtract 1.33 from each side to isolate x.
The outcome should be x=7.82-1.33, and if simplified x=6.49.
Thus your answer for #2 should be X=6.49, A.
For question #3 the first step you should take to approaching the equation is to isolate x by adding 15.99 towards each side of the equation.
The outcome should be x=58.06+15.99, and if simplified x=74.05.
Thus your answer for question #3 should be X=74.05, D.
Lastly, for question #4 the first step you should take towards isolating x is to divide the entire equation by 1.32.
Your outcome should be x= 6.8
Thus, your answer for the last question, #4, should be X=6.8, C.
Hope this helped!
-Blake
