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3 years ago

The population of unicorns is decreasing at a rate of 45% each year. What's the dependent quantity

1 answer:

5 0

The percent because the decreasing amount is independent, showing that because unicorns are decreasing the percent is dependent of the 45%. Hope this helped

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Can a radical ever be rational? Glve examples. Justify your answer using complete sentences.

pochemuha

Answer:

Yes

Step-by-step explanation:

Yes, a radical can be a rational, this is because a radical indicates the square root of a number. An example of this is $\sqrt{25}$ = 5.

4 0

3 years ago

Read 2 more answers

1. if √16 = x, then x^2

vivado [14]

1. A squares and square root cancels

2. CE square root of a perfect square is rational square root of non perfect squares are irrational

4. ✓16=4 ✓9 =3 therefore ✓10 will be between 4 and 3 which is 3.1 answer is C

4 0

3 years ago

Help me solve this please -22-x=5+6x+9

ollegr [7]

Answer: x = -5 1/7

Step-by-step explanation:

-22 - x = 5 + 6x + 9

First, combine the like terms 5 and 9

5 + 9 = 14

-22 - x = 14 + 6x

Add x to each side

-22 = 14 + 7x

Subtract 14 from each side

-36 = 7x

Divide each side by 7

x = -5 1/7 (Yes, a fraction.)

8 0

3 years ago

Given the data, as shown in the image below, determine if the distribution is uniformly distributed, symmetrically distributed,

Sedbober [7]

Answer:

The distribution is symmetric.

Step-by-step explanation:

The distribution will be skew left, if the data is more distributed on left side of graph.

The distribution will be right left, if the data is more distributed on right side of graph.

The distribution is symmetric if from the center, the data is distributed symmetrically, equal increase or decrease on either side.

The distribution is uniform if the value of data remains constant throughout the graph.

Above here, the from the center, the data decreases symmetrically on both the sides, same values of data for Cat-Rabbit pair and Dog-Mice pair.

Thus, distribution is symmetric.

8 0

2 years ago

Help I am very bad at math I need answers by tomorrow if you can help please do

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

= Cosec² A + Cosec² A - 1

= 2Cosec² A - 1 = RHS

$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$

3 0

3 years ago