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Elina [12.6K]
3 years ago
11

How can the equation of a parabola be derived when given the focus and the directrix?

Mathematics
1 answer:
Annette [7]3 years ago
4 0
The distance between any point (x0,y0) on the parabola and the focus (m,n) is the same as the distance between (x0,y0) and the directrix line ax+by+c. The distance between (x0,y0) and focus (a,b) is \sqrt((x-m)^2+(y-n)^2). The distance between (x0,y0) and ax+by+c is |ax0+by0+c|/\sqrt(m^2+n^2).  Equalize these two expressions.
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I need help plzzzz!!!!!!!!:)
Mila [183]

Answer:

B: y = -2/3x - 10/3

Step-by-step explanation:

The point is at (-2,-2), therefore when you input -2 into the desired equation, it should yield -2 as our output. If we use the equation B, the equation becomes

-4/3 - 10/3 which is -6/3. After dividing it we get -2 as the output.

To find the line yourself we use the point slope formula

y - y1 = m(x - x1)

The line is parallel to the one on the graph so the slope or <em>m</em> is equal to -2/3

We input the coordinates we want for y1 and x1.

y - (-2) = -2/3 (x - (-2))

y + 2 = -2/3x - 4/3

y + 6/3 = -2/3x - 4/3

y = -2/3x - 10/3

3 0
2 years ago
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
The longest sides of a rectangle are 3 inches less than six times the length of the shorter sides. The perimeter of the rectangl
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the shorter sides are 4 inches and the longer sides are 21 inches long

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I think the answer is B. because it says "waste of time"
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