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Kryger [21]
3 years ago
12

What is 10^{2} /19^{4}

Mathematics
1 answer:
MatroZZZ [7]3 years ago
4 0

Answer:

\frac{100}{130321}

Step-by-step explanation:

10² ÷ 19^{4}

100 ÷ 19^{4}

100 ÷ 130321

\frac{100}{130321}

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Complete this statement of the Quotient rule: v^k/v^h
alukav5142 [94]
The quotient rule is as follows

((l)•(h’) - (l’)•(h))/(l)^2

With l representing “low” or “bottom equation” and h representing “high” or “top equation”

Let’s plug in v^k and v^h in this case

((v^h)(v^k)’ - (v^h)’(v^k))/(v^h)^2
8 0
3 years ago
2.8y + 6 + 0.2y = 5y -15
Olegator [25]
Simplify 2.8y + 6 + 0.2y to 3y + 6

subtract 3y from both sides

simplify 5y - 15 - 3y to 2y - 15

add 15 to both sides

simplify 6 + 15 to 21

divide both sides by 2

switch sides

Answer: y = 21/2

*in decimal form this would be 10.5
6 0
4 years ago
Y = -4x Porportional or not?
Anit [1.1K]
They are proportional
5 0
4 years ago
Read 2 more answers
The Royal Fruit Company produces two types of fruit drinks. The first type is
Dimas [21]
Now, the percentage figures of say, 70%, 95% and so on, we'll use the decimal format of the, thus 70% is just 70/100 or 0.7 and 95% is just 95/100 or 0.95 and so on

so  \bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentration\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{70\% pure}&x&0.7&0.7x\\
\textit{95\% pure}&y&0.95&0.95y\\
-----&-----&-------&-------\\
mixture&160&0.85&(160)(0.85)
\end{array}

whatever "x" and "y" amounts are, we know, they must add up to 160 pints
thus  x + y = 160

now, whatever the concentrated amount of solute in the mixture, we know they must add up to 160*0.85 or 136

thus   0.7x + 0.95y = 136

thus    \bf \begin{cases}
x+y=160\implies \boxed{y}=160-x\\
0.7x+0.95y=136\\
----------\\
0.7x+0.95\left( \boxed{160-x} \right)=136
\end{cases}

solve for "x", to see how much of the 70% pure juice will be needed

what about "y"?  well, y = 160 - x
4 0
3 years ago
MATH<br> please help me with this question? i don’t understand it
LekaFEV [45]
The answer is 1.2

You just look at the graph at x = 6.
The point is marked as (-6, 1.2).
3 0
3 years ago
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