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lorasvet [3.4K]
3 years ago
11

Solve for x & round the answer to the nearest tenth

Mathematics
2 answers:
diamong [38]3 years ago
3 0
6/14 = 7/x
so
x = 7 * 14 / 6 
x = 98/6
x = 16.3

answer
D. x = 16.3



Ad libitum [116K]3 years ago
3 0
The large triangle & the small one are similar, since their respective bases are parallel. Then we can write:

(8+6)/6 = x/7.  and 14/6 = x/7 or 7/3 = x/7 . Cross multiplication:

7/3 = x/7 → 3x = 49 → x = 49/3 → x = 16.3 (Answer D)
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Rectangle PQRS is rotated 90 counterclockwise about the origin what are the coordinates of point Q
inna [77]
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.

When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)

Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)

point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)

point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)

Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)

Hope this helps :)
5 0
3 years ago
Read 2 more answers
The figure below shows a shaded region and a non-shaded region. Angles in the figure that appear to be right angles are right an
scoundrel [369]

Answer:Area of part 1:

A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

Area of part 2:

A2=length*width=(8+2)*1=10 ft2

Area of part 3:

A3=length*width=8*2=16 ft2

Total shaded area : A1+A2+A3=41 ft2

Total area of the reactangle : A=16*8=128 ft2

Total area of the nonshaded region : 128-41=87 ft2

Step-by-step explanation: Plz make brainliest

5 0
3 years ago
having trouble with this problem, pls help :/ I know the answer, just not how to get there. (ap calc ab, integrals)
pochemuha

Answer: D) 101

Step-by-step explanation:

By linearity, we can break it up into 2 integrals. The integral and derivative of f easily cancel out

\int\limits^{10}_{-1} {(2x+0.5f'(x))} \, dx =\int\limits^{10}_{-1} {2x} \, dx +0.5\int\limits^{10}_{-1} {f'(x)} \, dx =x^2|^{^{10}}_{_{-1}}+0.5f(x)|^{^{10}}_{_{-1}}\\=(100-1)+0.5(f(10)-f(-1))=99+0.5(8-4))=101

I used the table for values of f(x) at 10 and -1. Wouldn't be surprised if this was part of a series of questions about f because I really can't see how you could use the hypothesis that f is twice differentiable on R. Same for the other table values. I'm curious about how you found the answer. Was it a different way?

7 0
3 years ago
Add.<br><br> Express your answer in simplest form. <br><br><br> 5/10+3/10
AlexFokin [52]
Rules in adding fractions:

1) Make sure that they have common denominator.
5/10 + 3/10

2) Since both fraction have a denominator of 10, add the numerator and place the sum above the denominator

5/10 + 3/10 = (5 + 3)/10 = 8/10

3) Simplify the fraction
8/10 can still be simplified into 4/5

8 ÷ 2 = 4
10 ÷ 2 = 5

5/10 + 3/10 = 4/5
8 0
3 years ago
Read 2 more answers
Find a b if a = 3i + 8j and b = -0.5i -4j.
Gekata [30.6K]

Answer:

-33.5

Step-by-step explanation:

So this is a dot products vector problem, so the i and j represent x and y or horizontal and vertical components. So you multiple 3i and -0.5i and then separately multiply 8j and -4j. You get -1.5 and -32. Now all you have to do is add them and you get -33.5.

Basically in short:

1. Multiply the “i’s”.

2. Multiply the “j’s”.

3. Add the two products together.

HOPE THIS HELPS !! :-)

3 0
3 years ago
Read 2 more answers
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