The number of new ants appearing in Mark's bedroom each day can be found to be 12 ants per day
<h3>How to find the number of ants?</h3>
To find the number of new ants coming into Mark's room every day, you should divide the difference between the number of ants on consecutive days by the difference between the days since Mark moved in.
The difference between the number of ants from day 3 to 5 is:
= 90 - 66
= 24 ants
The difference in the number of days:
= 5 - 3
= 2 days
The number of new ants is therefore:
= 24 / 2
= 12 ants
Find out more on ants at brainly.com/question/13180306
#SPJ1
A] David's speed during the period:
i] AB
speed=distance/time
time taken between AB=0.5 hours
distance=20 km
thus
speed=20/0.5=40 km/h
ii]BC
time taken between BC=1.5 hours
distance=20
speed=20/1.5=13 1/3 km/h
b] Average speed for the entire time will be:
average speed=(total distance)/(total time)
total distance=(20+20+20)=60 km
total time=3 hours
thus
average speed=60/3=20 km/h
c] David's distance 2 hours and 15 minutes from the starting point was:
distance=20+20+10=50 km
Answer:
12cm
Step-by-step explanation:
Answer:
50%
Step-by-step explanation:
Let the total number of trees be T and suppose that this is made up of eucalyptus trees E and other kinds of trees, O.
Then E+O=T, and since 99% of the trees are eucalyptus trees, EE+O=0.99.
Therefore
0.99E+0.99O=E
0.01E=0.99O
E=99O.
Suppose we reduce the number of eucalyptus trees by some amount x and that the remaining number of eucalyptus trees are now 98% of the total trees.
Then we would have E−x(E−x)+O=0.98.
Therefore,
0.02(E−x)=0.98O
0.02E−0.02x=0.98O
0.02x=0.02E−0.98O
x=E−50(0.98)O
x=E−49O
x=E−49(E99)
x=5099E≈0.505050...×E.
So we end up removing a little over half of the eucalyptus trees. EDIT: Forgot to mention - removing 50.505050...% of the eucalyptus trees means that we are removing 0.50505050....×0.99T which is 0.5T or half the trees in the neighborhood.
