Answer: 0.25 or 1/4
Step-by-step explanation:
1/2*2 = 1/2^2 = 1/4
Answer:
Step-by-step explanation:
let x,y be the sides of court.
2(x+y)=90
x+y=90/2=45
y=45-x
xy=500
x(45-x)=500
45x-x²=500
x²-45x+500=0
x²-25x-20x+500=0
x(x-25)-20(x-25)=0
(x-25)(x-20)=0
x=25,20
when x=25
y=45-x=45-25=20
when x=20
y=45-20=25
sides are 25 ft,20 ft.
R^2=(x-6)^2+(y-4)^2
r^2=(6-2)^2+(4-1)^2, r^2=16+9=25
(x-6)^2+(y-4)^2=25
Answer:
<em>Each classroom received 120 gifts and the hospital received 12 gifts</em>
Step-by-step explanation:
<u>Division As Evenly Distribution</u>
The first concept we manage when learning about divisions is how to distribute an amount N among m elements such as everyone receives the same amount.
If the nature of the problem allows distributing decimal portions of N, then every receiver gets exactly the same amount N/m.
But things are different when the division must be an integer number. For example, if we wanted to divide gifts, we cannot give partial gifts. So the correct division is a matter of the study of integer numbers.
If N is divisible by m, i.e. there is no remainder in the division, then each element will receive N/m gifts. But what if they are not divisible? We must divide and take the integer part of the division and discard the remainder
We want to divide 2,292 gifts to the school, where there are 19 classrooms. If we divide 2,292/19 we get 120 and a remainder of 12.
Answer. Each classroom received 120 gifts and the hospital received 12 gifts
Answer:

Step-by-step explanation:
Total possibilities when we a roll a die at a time are 6
given we should have four for first time and then three
let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is
PROBABILITY=
Favourable chances=1
Total chances=6
Probability=
the prabability to get 4 in first roll is
.
let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is
Favourable chances=1
total chances=6
probability=
the probability to get 3 in second roll irrespective of first one is 
the probability to get 4 in first time and then 3 is
The probability to occur both events at a time is multiplication of individual probabilities
So,
probablility to get 4 in first roll=
probability to get 3 in second roll=
probability to occur both at a same time is =

=