Question

Which is the equation of a trend line that passes through the points (7, 450) and (14, 401)?

Answer 1

Answer: $y+7x=499$

Step-by-step explanation:

The equation of a line  passes through the points (a,b) and (c,d) is given by :-

$(y-b)=\frac{d-b}{c-a}(x-a)$

Hence, the equation of a line  passes through the points (7, 450) and (14, 401) is given by :-

$(y-450)=\frac{401-450}{14-7}(x-7)\\\\\Rightarrow y-450=\frac{-49}{7}(x-7)\\\\\Rightarrow y-450=-7x+49\\\\\Rightarrow y+7x=49+450\\\\\Rightarrow y+7x=499$

Answer 2

Answer:

y = -7x + 499