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il63 [147K]
4 years ago
7

I need help with this problem: A 12-member committee is going to choose a chairman, vice-chairman, and secretary. In how many wa

ys can these people be chosen? A. 36 ways B. 1320 ways C. 1728 ways D. 79,833,600 ways
Mathematics
1 answer:
Ilia_Sergeevich [38]4 years ago
5 0
So 12 members
they have 3 slots
assuming they choose from the group of 12 members
12 choices for the first slot
2nd slot: 1 is taken so 12-1=11 choices for the second
3rd slot: 2 are taken so 12-2=10 choices for te 3rd

answer is 12 times 11 times 10=1320=B

the answer is B
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Answer:

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Your goal here is to REDUCE the given expression to simplest terms.

One way in which to approach this problem would be to rewrite (2x^2y^10)^3 as:  (2x^2*y^8)*y^2*(2x^2*y^10)^2.

Dividing this rewritten expression by 2x^2*y^8 results in:

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Multiply this by y^2 (see above):

y^2*4x^4*y^20

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Finally, this should be re-written as

                                    4*x^4*y^22

Another way of doing this problem would involve expanding the numerator fully and then cancelling out like factors:

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