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AVprozaik [17]
3 years ago
12

What is the absolute deviation for 62 in the data set?

Mathematics
1 answer:
makvit [3.9K]3 years ago
8 0
D is the answer for this question:))
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What is the value of x? (5 points)
Ahat [919]
I’m pretty sure the answer is 30!
3 0
3 years ago
Read 2 more answers
The radius of the circle is increasing at a rate of 2 meters per minute and the sides of the square are increasing at a rate of
Lunna [17]

Answer:

Change in area=24\pi-48

Step-by-step explanation:

Let s will be the side of square and r will be the radius of circle.

Then two given conditions are

1)dr/dt=2 m/s

2)ds/dt=1 m/s

Area enclosed=(Area of square)-(Area of circle)

Area of square=s^{2}

Area of circle=\pi r^{2}

Area enclosed=(\pi  r^{2})-s^{2}

dA/dt=2\pir(dr/dt)-2s(ds/dt)

At s=24,and r=6

dA/dt=2(\pi)(6)(2)-2(24)(1)

Change in area=24\pi-48

6 0
2 years ago
SOMEONE.HALP.ME.
Natasha2012 [34]
3/4 = 0.75 in decimal inch
Karla wants to leave 0.75 inch in her signature.
4 -0.75 = 3.25 inch needed
0.25 = 1/4

3 and 1/4 inches is needed.
3 0
3 years ago
2/5 times 15/17 times 3/4 =
Dahasolnce [82]
2/5*15/17*3/4
= 2*15*3/5*17*4
= 2*15*3/340
= 90/340
=90/34
 hope this helps hope I'm right :)

4 0
3 years ago
Ray QS bisects PQR. IF PQS= 3X AND RQS=2X÷6 THEN PQR IS?
OleMash [197]

It is given in the question that QS bisects angle PQR .

m \angle PQS = 3x , m \angle RQS =2x+6

And since, QS bisects angle PQR, therefore

[tex]m \angle PQS = m \angle RQS[/tex]

Substituting the values of angle PQS and angle RQS, we will get

3x = 2x+6
\\
3x-2x=6
\\
x = 6

PQR is twice of angle PQS. Therefore angle PQR is

m \angle PQR = 2*3*6 = 36 degree

6 0
3 years ago
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