I’m pretty sure the answer is 30!
Answer:
Change in area=24
-48
Step-by-step explanation:
Let s will be the side of square and r will be the radius of circle.
Then two given conditions are
1)dr/dt=2 m/s
2)ds/dt=1 m/s
Area enclosed=(Area of square)-(Area of circle)
Area of square=
Area of circle=
Area enclosed=
dA/dt=2
r(dr/dt)-2s(ds/dt)
At s=24,and r=6
dA/dt=2(
)(6)(2)-2(24)(1)
Change in area=24
-48
3/4 = 0.75 in decimal inch
Karla wants to leave 0.75 inch in her signature.
4 -0.75 = 3.25 inch needed
0.25 = 1/4
3 and 1/4 inches is needed.
2/5*15/17*3/4
= 2*15*3/5*17*4
= 2*15*3/340
= 90/340
=90/34
hope this helps hope I'm right :)
It is given in the question that QS bisects angle PQR .

And since, QS bisects angle PQR, therefore
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Substituting the values of angle PQS and angle RQS, we will get

PQR is twice of angle PQS. Therefore angle PQR is
