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Viefleur [7K]
3 years ago
13

Julius needs to determine how much information needs to be given about an isosceles triangle to be able to draw an isosceles tri

angle. He is looking at six different cases and is trying to determine if that amount of detail will allow him to construct just one isosceles triangle or if it allows for more than one isosceles triangle.
Mathematics
1 answer:
Brrunno [24]3 years ago
3 0

Answer:

Six cases are enough to construct more than one isosceles triangle

Step-by-step explanation:

An Isosceles triangle is a triangle in which at least two of it's sides are congruent.

If two of the three sides of a triangle are congruent, but the third side is of a different length, the triangle is isosceles.

If all three sides of the triangle are congruent, even though this is an equilateral triangle, it satisfies the condition of an isosceles, and it is ok to still it isosceles.

Julius might decide to split information for a better explanation, it doesn't matter the number of cases he has, but six cases should be enough to draw an isosceles triangle.

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There are 40 people at Drake’s sweet sixteen party. Drake’s only rule is that everyone in the party must meet and shake each oth
Nonamiya [84]

Answer:

Given:

Total Number of people at the Drake’s sweet sixteen party = 40

Everyone in the party must meet and shake each other’s hand

1) How many handshakes are there altogether?

There was total of 780 handshakes in the party.

2. How did you get your solution:

If you have 7 people, person seven shakes six other hands, person  

six shakes five other hands, person five shakes fours other hands,  

person  ,four shakes three other hands, person three shakes two other hands,  and person two shakes one hand.  Another way to see it is,

Person 7  +person 6 + person 5 + person 4 +person 3 + person 2 +  person 1

= 6+5+ 4+3+2+1

=>21

so similairly in case of 40 persons

= 39+38+37+36+37+36+35+34 .................+3+2+1

=>780

3) What’s the quickest way to figure this out if Drake invited 1,000 people?

People at Party               Number of Handshakes

     2                                                     1

     3                              1 + 2              = 3

     4                            1 + 2 + 3          = 6

     5                          1 + 2 + 3 + 4      = 10

     6                        1 + 2 + 3 + 4 + 5  = 15

     .

     .

     .                                          

     n                              1 + 2 + ...+ (n-1) =  --------     \frac{n(n-1)}{2}

Hence for n persons the number of handshakes will be  \frac{n(n-1)}{2}

So for 1000 persons the number of handshakes will be

=>\frac{1000(1000-1)}{2}

=>\frac{1000(999)}{2}

=>\frac{999000}{2}

=>499,500

                                                     

3 0
3 years ago
Can y'all help me on 1,2,3,4,5,6,7
victus00 [196]
Look up the answers on google. Just look up lesson 3-2 rate of change and slope practice and problem solving: C
You should find all the answers there
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