Question

9[[w]^[5]]+24[[w]^[4]]+16[[w]^[3]] I need to simplify this.

Answer 1

9(w⁵ + 24w⁴ + 16w³)
9(w⁵) + 9(24w⁴) + 9(16w³)
9w⁵ + 216w⁴ + 144w³

Answer 2

$9w^5 + 24w^4 + 16w^3$

Factor out w³.

$w^3(9w^2+24w+16)$

Find two numbers that multiply to equal 144 (9*16) and add to equal 24.
This would be 12 and 12.

$w^3(9w^2+12w+12w$

Factor.

$w^3(3w(3w+4)+4(3w+4))$+16)[/tex]

Simplify.

$w^3(3w+4)(3w+4) = w^3(3w+4)^2$