All categories

3 years ago

Solve addition and subtraction word problems using the ruler as a number line

1 answer:

5 0

Its just like using your hand only difference is a ruler unless its a point in it it goes into segments like quarters etc.

You might be interested in

Marco scored 1,753 points

enyata [817]

Answer:

All you have to do is subtract!

<em>1753 - 887</em> = 866

Therefore, Marco scored 866 more points than Jasmine. Hope this helped! :)

3 0

3 years ago

The two triangles are congruent as suggested by their appearance. Find the value of c. The diagram is not to scale.

Nostrana [21]

C = 4
Use the formula a^2 + b^2 = c^2
5 = a and 4 = b

3 0

3 years ago

HELP!!!!

ch4aika [34]

Answer:

$8 y^{50}$

Step-by-step explanation:

Given (64 y Superscript 100 Baseline) Superscript one-half.

Let us write it into an equation.

$\left(64 y^{100}\right)^{\frac{1}{2}}$

Apply radical rule: $\sqrt[n]{a}=a^{\frac{1}{2}}$ and $a^{m+n}=a^m+a^n$

$\begin{aligned}\left(64 y^{100}\right)^{\frac{1}{2}} &=\sqrt[2]{64 y^{100}} \\&=\sqrt[2]{8^{2} y^{50} y^{50}} \\&=\sqrt[2]{8^{2}\left(y^{50}\right)^{2}} \\&=8 y^{50}\end{aligned}$

Hence, $8 y^{50}$ is equivalent to (64 y Superscript 100 Baseline) Superscript one-half.

8 0

3 years ago

(11,2) m-7 how do you write in slope form

lara31 [8.8K]

Answer:

y=7x-75

Step-by-step explanation:

use poiint slope formula

8 0

3 years ago

Jack bought a new car in 2014 for 28,000. If the value of the car decreases by 14% each year, write an exponential model for the

elena55 [62]

Answer:

In 2026 car will have a value of $5,000.

Step-by-step explanation:

We have been given that Jack bought a new car in 2014 for 28,000. If the value of the car decreases by 14% each year.

Since we know that an exponential function is in form: $y=a*b^x$ , where,

a = Initial value,

b = For decay or decrease b is in form (1-r), where r represents decay rate in decimal form.

Let us convert our given decay rate in decimal form.

$14\%=\frac{14}{100}=0.14$

Upon substituting a =28,000 and r=0.14 in exponential decay function we will get,

$y=28,000(1-0.14)^x$ , where x represents number of years after 2014.

Therefore, the function $y=28,000(0.86)^x$ represents the value of car x years after 2014.

To find the number of years it will take to car have the value of $5,000, we will substitute y=5,000 in our function.

$5,000=28,000(0.86)^x$

Let us divide both sides of our equation by 28,000.

$\frac{5,000}{28,000}=\frac{28,000(0.86)^x}{28,000}$

$0.1785714285714286=(0.86)^x$

Let us take natural log of both sides of our equation.

$ln(0.1785714285714286)=ln((0.86)^x)$

Using natural log property $ln(a^b)=b*ln(a)$ we will get,

$ln(0.1785714285714286)=x*ln(0.86)$

$\frac{ln(0.1785714285714286)}{ln(0.86)}=\frac{x*ln(0.86)}{ln(0.86)}$

$\frac{-1.7227665977411033893}{-0.1508228897345836}=x$

$x=11.422447\approx 12$

As in the 12th year after 2014 car will have a value of $5,000, so we will add 12 to 2014 to find the year.

$2014+12=2026$

Therefore, in 2026 car will have a value of $5,000.

6 0

3 years ago

Read 2 more answers