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Karo-lina-s [1.5K]
3 years ago
14

Determine the value of the variable in the simplified expressions. What is the value of X? Gx+h^-3=1/g^6+1/h^3. X=_____. What is

the value oy Y? B^4c^-7 = b^y/c7 Y=_____
Mathematics
2 answers:
marshall27 [118]3 years ago
6 0

Answer:

-6 and 4

Step-by-step explanation:

swat323 years ago
5 0

Answer:

x=-6

y=4

Step-by-step explanation:

i just took the quiz

hope i could help

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X= -7

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Solve for x. a=1/2h(b x)
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2a = h(b + x)
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N-31/4 =2 simple equation
Zanzabum

Answer:

n = 5.75

Step-by-step explanation:

original equation

n - 31/4 = 2

multiply everything by 4

n * 4 - 31/4 * 4 = 2 * 4

simplify

4n - 31 = 8

add 31 to both sides

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6 0
3 years ago
In this exercise, we estimate the rate at which the total personal income is rising in a metropolitan area. In 1999, the populat
DiKsa [7]

Answer:

the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion

Step-by-step explanation:

From the given information:

Let consider y to represent the number of years after 1999

Then the population in time (y) can be expressed as:

P(y) = 9400y + 924900

The average annual income can be written as:

A(y) = 1400y + 30388

The total personal income = P(y)  ×  A(y)

The rate at which the total personal income is rising is T'(y) :

T'(y) = P'(y)  ×  A(y)  + P(y)  ×  A'(y)

T'(y) = (9400y + 924900)' (1400y + 30388) + (9400y + 924900) (1400y + 30388)'

T'(y) = 9400(1400y + 30388) + (9400y + 924900) 1400

Since in 1999 y =0

Then:

T'(0) = 9400(1400(0) + 30388) + (9400(0) + 924900) 1400

T'(0) = 9400(30388) + (924900)1400

T'(0) = $1,580,507,200 billion

Therefore; the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion

8 0
3 years ago
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