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3 years ago

Solve the following quadratic equations using completing the square x2 + 10x + 55 = 0

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

3 0

Is the “x2” supposed to be x squared?

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20% of which number is 30? A. 1.5 B. 6 c. 15 D. 150 E. 600

MrMuchimi

B is the correct answer

6 0

3 years ago

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Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2, 0)A(2,0)A

const2013 [10]

9514 1404 393

Answer:

28 square units

Step-by-step explanation:

The rectangle is 7-0 = 7 units high and 6-2 = 4 units wide. Its area is the product of these dimensions:

A = LW

A = (7)(4) = 28 . . . square units

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3 years ago

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Write an equation for each description. solve for x

kipiarov [429]

Answer:

x = 33

Step-by-step explanation:

Because of the little square we know the total angle is 90

24 + 2x = 90

-24

2x = 66

x = 33

6 0

3 years ago

66.21 was rounded to 2dp. what is the lower bound?

sladkih [1.3K]

Answer:

the answer is 66.205

Step-by-step explanation:

basically you look at the place value so

66.21 is basically the same as 66.210 then you look at the lowest number that can round UP to 66.210 which would be out of 1 to 9 would be 5 so the smallest number that can round up to 66.210 is 66.205 hope this helped :D

4 0

3 years ago

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

3 years ago