If X is a random variable representing the number of children that end up having light-colored eyes, then X follows a binomial distribution with success probability p = 0.25 and number of trials n = 5.

The variance of a binomial distribution with these parameters is n p (1 - p), so the variance in this case would be

5 • 0.25 • (1 - 0.25) = 0.9375 ≈ 0.9

4 0

2 years ago

PLEASE HELP!!!!!!!dgbdgdbhdndcn

bogdanovich [222]

Problem 1)

AC is only perpendicular to EF if angle ADE is 90 degrees

(angle ADE) + (angle DAE) + (angle AED) = 180
(angle ADE) + (44) + (48) = 180
(angle ADE) + 92 = 180
(angle ADE) + 92 - 92 = 180 - 92
angle ADE = 88

Since angle ADE is actually 88 degrees, we do NOT have a right angle so we do NOT have a right triangle

Triangle AED is acute (all 3 angles are less than 90 degrees)

So because angle ADE is NOT 90 degrees, this means AC is NOT perpendicular to EF

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Problem 2)

a) The center is (2,-3)

The center is (h,k) and we can see that h = 2 and k = -3. It might help to write (x-2)^2+(y+3)^2 = 9 into (x-2)^2+(y-(-3))^2 = 3^3 then compare it to (x-h)^2 + (y-k)^2 = r^2

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b) The radius is 3 and the diameter is 6

From part a), we have (x-2)^2+(y-(-3))^2 = 3^3 matching (x-h)^2 + (y-k)^2 = r^2

where
h = 2
k = -3
r = 3

so, radius = r = 3
diameter = d = 2*r = 2*3 = 6

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c) The graph is shown in the image attachment. It is a circle with center point C = (2,-3) and radius r = 3.

Some points on the circle are

A = (2, 0)
B = (5, -3)
D = (2, -6)
E = (-1, -3)

Note how the distance from the center C to some point on the circle, say point B, is 3 units. In other words segment BC = 3.

6 0

3 years ago

Solve for x y=×/c+b

Alex17521 [72]

$\text{Hello there!}\\\\\text{Solve for x:}\\\\y=\frac{x}{c}+b\\\\\text{Multiply both sides by c to cancel the c out of the denominator}\\\\yc=x+bc\\\\\text{Subtract both sides by bc}\\\\yc-b=x\\\\\boxed{\text{Answer: yc - bc = x}}$

6 0

3 years ago