Answer: a) 0.0792 b) 0.264
Step-by-step explanation:
Let Event D = Families own a dog .
Event C = families own a cat .
Given : Probability that families own a dog : P(D)=0.36
Probability that families own a dog also own a cat : P(C|D)=0.22
Probability that families own a cat : P(C)= 0.30
a) Formula to find conditional probability :
(1)
Similarly ,
Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792
b) Again, using (2)
Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264
I hope this helps you
9x-2=12
9x=14
x=14/9
x= 1,555555
1 <1,5555 <2
B
5(3+1)
5*(4)
=20
The answer is 20
The dot-plot for the data is sketched at the end of this answer.
--------------------------
- The dot plot shows the <u>number of times each measure appears in the data-set.</u>
<u />
- 68 appears once, thus it is 1 in the dot-plot.
- 69 appears three times, thus it is 3 in the dot-plot.
- 70 appears once, thus it is 1 in the dot-plot.
- 71 does not appears, so it is 0.
- 72 appears once, thus it is 1 in the dot-plot.
- 73 appears five times, so it is 5 in the dot-plot.
- 74 appears once, thus it is 1 in the dot-plot.
- 75 does not appears, so it is 0.
- 76 appears twice, thus it is 2.
- 77 appears once, so it is 1.
The sketch is given at the end of this answer.
A similar problem is given at brainly.com/question/24908406
