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Lynna [10]
3 years ago
8

Under what conditions can the t-distribution be correctly employed to test the difference between two population means?

Mathematics
1 answer:
vova2212 [387]3 years ago
4 0
Home me work is kewl stay in skweel
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A contemporary building has a window in the shape of a parallelogram with a base of 90 in and an adjacent side of 40 in. How man
BaLLatris [955]

260 inches of trim are needed to surround the​ window.

<h3 /><h3>What is the surface area?</h3>

The total land area of all the faces of a three-dimensional object is its surface area. When we wish to wrap something in real life, we employ the notion of surface areas of distinct things.

Actually, all we need is a trim that is the same size as our window and equal to the parallelogram's circumference, which is

The sum of the side is;

⇒Length of lower side + Length of the upper side

⇒ 90+90

⇒180 inches

The sum of adjacent sides;

Sum of adjacent sides  =  40+40

Sum of adjacent sides  = 80 inches

The length you should trim is needed to surround the​ window is found as;

⇒ 180 inches + 80 inches

⇒260 inches

Hence,260 inches of trim are needed to surround the​ window.

To learn more about the surface area, refer to the link;

brainly.com/question/2835293

#SPJ1

7 0
2 years ago
120540000 in word form and expanse from
valina [46]
One hundred twenty million five hundred forty thousand<span />
8 0
3 years ago
Read 2 more answers
How do you count by 8s and 7s
galben [10]

Answer:

just add 8+8+8 until you get to the number u want/need and the same with 7. Or you can multiply.

8x1=8

7x1=7

8x3=24        (8+8+8=24)

7x3=21         (7+7+7=21)

etc.


Hope it helps!

7 0
3 years ago
Sin(x+20) - cos (2X+10)
Vladimir [108]

Answer:

X=20

Step-by-step explanation:

Sin(x+20)=cos(2x+10)

Sin(x+20)=sin(90-(2x+10)

X+20=90-2x-10

3x=60

X=20

8 0
3 years ago
A point charge q1 = 3.30nC is located on the x-axis at x= 1.90m , and a second point charge q2= -6.40 nC is on the y-axis at y=
Dahasolnce [82]

Answer:

Step-by-step explanation:

charge q1 is placed at x = 1.90 m and the charge q2 is placed at y = 1.15 m

here, the charge enclosed in a sphere is zero as the radius of sphere is 0.625 m which is less than the x = 1.90 m and y = 1.15 m. So by the Gauss's theorem,

\phi =\frac{q}{\epsilon _{0}}

where q is the charge enclosed, as the charge enclosed is zero so the electric flux is zero.

3 0
3 years ago
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