All categories

3 years ago

Under what conditions can the t-distribution be correctly employed to test the difference between two population means?

Mathematics

1 answer:

vova2212 [387]3 years ago

4 0

Home me work is kewl stay in skweel

You might be interested in

10 cm<br> 12 cm<br> 10 cm<br> 6 cm<br> 18 cm

WARRIOR [948]

WHATS THE QUESTION??????

3 0

3 years ago

Read 2 more answers

Which expression is equivalent to (2x − 3)(x + 4) ?

sergey [27]

Answer:

Step-by-step explanation:

2x2 + 8x - 3x - 12

2x2 + 5x - 12 is equivalent to the given expression

7 0

3 years ago

Read 2 more answers

50 – 5(4.3 – 1.3) ÷ 0.5

marissa [1.9K]

Answer:

(0.5, 1.3)(0.5, 1.3)

Step-by-step explanation:

Given equations are:

As we can see that the given equations are linear equations which are graphed as straight lines on graph. The solution of two equations is the point of their intersection on the graph.

We can plot the graph of both equations using any online or desktop graphing tool.

We have used "Desmos" online graphing calculator to plot the graph of two lines (Picture Attached)

We can see from the graph that the lines intersect at: (0.517, 1.267)

Rounding off both coordinates of point of intersection to nearest tenth we get

(0.5, 1.3)

Hence,

(0.5, 1.3) is the correct answer

Keywords: Linear equations, variables

4 0

3 years ago

Read 2 more answers

Find the surface area of a cylinder with a diameter of 18 and a height of 32. Use 3.14 for π. Round your answer to the nearest t

Ksenya-84 [330]

Answer: a = 2,315.5

Step-by-step explanation:

a = 2πrh+2πr²

a = 2π(9)(32) + 2π9²

a = 2π x 288 + 2π x 81

a = 1809.6 + 508.9

a = 2,315.5

(pls mark me the brainliest)

(theres a button that says "mark brainliest" on my answer)

7 0

3 years ago

Solve square root of x + square root of x+2 = 2

andrew-mc [135]

The value of x is $\frac{1}{4}$

Step-by-step explanation:

Given:

$\sqrt{x} + \sqrt{x + 2} = 2$

Rearranging the radical on left side,

$\sqrt{x + 2} = 2 - \sqrt{x}$

Power on both sides,

$(\sqrt{x + 2})^{2} = (2 - \sqrt{x})^{2}$

Simplifying the left,

$x + 2 = (2 - \sqrt{x} )^{2}$

For the RHS equation, use the property of (a-b)² = (a²-2ab+b²),

$= > x + 2 = {2}^{2} - (2 \times 2 \sqrt{x}) + ( \sqrt{x})^{2}$

Now calculating its powers,

$= > x + 2 = 4 - 4\sqrt{x} + x$

Now sending -4√x to the LHS (left side), its sign becomes plus (+),

$= > 4 \sqrt{x} = 4 + x - x - 2$

Now the +x and -x will be cancelled,

$= > 4 \sqrt{x} = 4 - 2$

$= > 4 \sqrt{x} = 2$

Bringing 4 to the right side, it becomes the denominator,

$= > \sqrt{x} = \frac{2}{4}$

$= > \sqrt{x} = \frac{1}{4}$

Now powering both sides,

$= > ( \sqrt{x})^{2} = ( \frac{1}{2})^{2}$

$= > x = \frac{1}{4}$

4 0

3 years ago