namely, what is 1/2 of 3/4, well, is just their product.

If all three side lengths are INTEGERS and form PYTHAGOREAN TRIPLE then we know decimals are not allowed
if 24 and 51 are both legs then

x = 3177
and squre root of that gives us 56.364.... NOT an integer
So that means one of them is not a leg and since hypotenuse is longer than both legs, 51 must be the hypotenuse so to get the third side
![51^{2} - 24^{2} = x^{2}[tex] [tex] x^{2}](https://tex.z-dn.net/?f=%2051%5E%7B2%7D%20-%20%2024%5E%7B2%7D%20%20%3D%20%20x%5E%7B2%7D%5Btex%5D%20%5Btex%5D%20x%5E%7B2%7D%20)
=2025
x=45, leg B
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
x = 2
Step-by-step explanation:
3.x + y = 11 (eq 1)
Y = x + 3 (eq 2)
sub 2 into 1
3x + x + 3 = 11
4x + 3 = 11
4x = 8
x = 2
Answer:
9.000000001
Step-by-step explanation:
If the hypotenuse is 15, the ladder, facing the right angle, and the opposite is 12 we need to use SOH to find the angle.
sin of angle is opposite / hypotenuse
sin of angle is 12 / 15
12/15 = 0.8
sin^-1 of 0.8 = 53.13010235
Angle is that
Then we do this again but a different equation
cos of angle is adjacent (x which we are looking for) / hypotenuse
cos of 53.13... is x / 15
(15 x cos of 53.13... )is x
So 15 x cos of 53.13... is 9.000000001 feet away.