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2 years ago

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What are levels of mathematical acquisition in pre-junior

1 answer:

forsale [732]2 years ago

4 0

Answer: Number Sense – Understanding Quantity.

Representation – Using Symbols and Words to Represent Numbers.

Shapes and Spatial Relationships (Geometry)

Measurement – Comparing and Communicating about size.

Patterns – Recognizing and Making Patterns.

Problem Solving.

Step-by-step explanation: boom!

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Solve the system of linear equations below. 4x - 3y = 17 5x + 4y = 60

LenaWriter [7]

4x-3y=17......(1)
5x+4y=60......(2)

Multiply equation (1) by 4 and equation (2) by 3:-

16x - 12y = 68
15x + 12y = 180

Adding these 2 equations:_

31x = 248
x = 248/31 = 8

Now substitute x = 8 in equation (1):-

4(8) - 3y = 17
32-3y = 17
-3y = -15
y = -15/-3 = 5

So solution is x=8,y=5

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3 years ago

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Answer:

Wheres the question

Step-by-step explanation:

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3 years ago

Please please help me What is 5% of 200?

Leni [432]

Answer:

10

Step-by-step explanation:

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3 years ago

Read 2 more answers

Please help and answer has an exponent

Len [333]

2^6 (or two to the sixth power) is equal to 4^3, which equals out to 64.

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1 year ago

Given the functions f(x) = 4x2 − 1, g(x) = x2 − 8x + 5, and h(x) = –3x2 − 12x + 1, rank them from least to greatest based on the

tangare [24]

Answer:

Option D) h(x), f(x), g(x)

Step-by-step explanation:

we know that

The axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex of the parabola

Part 1) we have

$f(x)=4x^{2} -1$

This is a vertical parabola open upward

The vertex is a minimum The vertex is the point (0,-1)

The x-coordinate of the vertex is 0

so

The axis of symmetry is x=0

Part 2) we have

$g(x)=x^{2}-8x+5$

This is a vertical parabola open upward

The vertex is a minimum

Convert the equation into vertex form

$g(x)-5=x^{2}-8x$

$g(x)-5+16=x^{2}-8x+16$

$g(x)+11=x^{2}-8x+16$

$g(x)+11=(x-4)^{2}$

$g(x)=(x-4)^{2}-11$

The vertex is the point (4,-11)

The x-coordinate of the vertex is 4

so

The axis of symmetry is x=4

Part 3) we have

$h(x)=-3x^{2}-12x+1$

This is a vertical parabola open downward

The vertex is a maximum

Convert the equation into vertex form

$h(x)-1=-3x^{2}-12x$

$h(x)-1=-3(x^{2}+4x)$

$h(x)-1-12=-3(x^{2}+4x+4)$

$h(x)-13=-3(x+2)^{2}$

$h(x)=-3(x+2)^{2}+13$

The vertex is the point (-2,13)

The x-coordinate of the vertex is -2

so

The axis of symmetry is x=-2

Part 4) Rank their axis of symmetry from least to greatest

1) h(x) -----> axis of symmetry -2

2) f(x) -----> axis of symmetry 0

3) g(x) -----> axis of symmetry 4

so

h(x),f(x),g(x)

7 0

3 years ago