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SVEN [57.7K]
3 years ago
6

Please help I need help with this homework ASAP!!

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0
8/12 and 4/6 and10/15 and20/30 and 40/60
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An economist wants to estimate the mean per capita income (in thousands of dollars) for a major city in Texas. Suppose that the
Arisa [49]
The answer is 50%...
5 0
2 years ago
Identify the domain and range of y = 4x - 5 + 3
Zepler [3.9K]

Answer:

\huge\boxed{\text{Domain:}\ D=\mathbb{R}=(-\infty;\ \infty)}\\\boxed{\text{Range:}\ R=\mathbb{R}=(-\infty;\ \infty)}

Step-by-step explanation:

y = 4x - 5 + 3 = 4x - 2

It's an equation of a line in the slope-intercept form.

y = 4x - 2 → f(x) = 4x - 2 - it's a lienar function.

The domain of a linear function is the set of all real numbers.

If a slope of linear function is different than 0, then the range is the set of all real numbers.

5 0
3 years ago
Order the group of quadratic functions from widest to narrowest graph <br> y=3^2, y=5^2, y=7^2
Sedbober [7]
Y = 7^2
y = 5^2
y = 3^2

if wide is the greatest and narrow means smallest then i hope its right

Ur Welcome and if its wrong plz let me know and i will fix it,
xXharleyquinn04Xx
7 0
3 years ago
Today the 6th graders had 5 students absent, the 7th graders had 8 students absent,and the 8th graders had 9 students absent. If
Irina18 [472]
All you have to do is multiply 8 by 20 which is 160
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3 years ago
Janet deposited $9,600 into an account that pays 4.4 interest, compounded daily. At the end of nine months, how much interest ha
neonofarm [45]

bearing in mind that 9 months is not even a year, but since there are 12 months in a year, then 9 months is really 9/12 years.


\bf ~~~~~~ \stackrel{\textit{daily}}{\textit{Continuously}} \textit{Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$9600\\ r=rate\to 4.4\%\to \frac{4.4}{100}\dotfill &0.044\\ t=years\to \frac{9}{12}\dotfill &\frac{3}{4} \end{cases} \\\\\\ A=9600e^{0.044\cdot \frac{3}{4}}\implies A=9600e^{0.033}\implies A\approx 9922.09 \\\\\\


\bf \stackrel{\textit{interest earned}}{9922.09-9600\implies 322.09}

5 0
3 years ago
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