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Leona [35]
3 years ago
7

Today the 6th graders had 5 students absent, the 7th graders had 8 students absent,and the 8th graders had 9 students absent. If

the attendance follows the same trend for the month (assume 20 days) how many times will a 7th grade student be absent during the month?
Mathematics
1 answer:
Irina18 [472]3 years ago
7 0
All you have to do is multiply 8 by 20 which is 160
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HELP PLEASE I NEED TO GET IT DONE BECAUSE ILL BE WITH MY FAMILY AT THANKSGIVING TOMORROW
dalvyx [7]

Answer:

6

Step-by-step explanation:

Straight line is 180

square = right angle=90

180-90=90

5x+(x+54)=90

6x+54=90

6x=36

x=6

Hope this helps :D

6 0
3 years ago
What's 676 divided by 13 in long division? I need step by step cause you have to drag the numbers.
Galina-37 [17]

Answer: 52

Step-by-step explanation: Not much work with this one but hope this helps :)

3 0
2 years ago
Please help ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing.
sweet [91]

Answer:

  D.  Minimum at (3, 7)

Step-by-step explanation:

We can add and subtract the square of half the x-coefficient:

  y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2

  y = (x -3)^2 +7 . . . . . simplify to vertex form

Comparing this to the vertex for for vertex (h, k) ...

  y = (x -h)^2 +k

We find the vertex to be ...

  (3, 7) . . . . vertex

The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.

5 0
3 years ago
Find the explicit formula for the given sequence 1/4, 3/4, 5/4, 7/4​
Harlamova29_29 [7]

Step-by-step explanation:

d=(3/4)-(1/4)=(5/4)-(3/4)=(7/4)-(5/4)=1/2

then it is an arithmetic sequence

by using this equation :

a(n) = a1 +(n-1)d

and we have : a1=(1/4),  d=(1/2)

So:

Explicit formula: a(n) = (1/4) +(n-1)*(1/2)

<em>hope this helps </em>

<em />

8 0
3 years ago
Read 2 more answers
Given that y=x^(1/3) , use calculus to determine an approximate value for ∛8030
Alex777 [14]
F(x) = x^(1/3)
f(8000) = 8000^(1/3) = 20

f'(x) = 1/3 * x^(-2/3)
f'(x) = 1/(3x^(2/3))
f'(8000) = 1/(3*8000^(2/3)) = 1/(3*400) = 1/1200

Linear approximation for f(x) about x = 8000
L(x) = f(8000) + f'(8000) (x−8000)
L(x) = 20 + 1/1200 (x−8000)

8030^(1/3) ≈ L(8030)
= 20 + 1/1200 (8030−8000)
= 20 + 30/1200
= 20 + 1/40
= 20.025
8 0
2 years ago
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