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3 years ago

7

Today the 6th graders had 5 students absent, the 7th graders had 8 students absent,and the 8th graders had 9 students absent. If

the attendance follows the same trend for the month (assume 20 days) how many times will a 7th grade student be absent during the month?

1 answer:

Irina18 [472]3 years ago

7 0

All you have to do is multiply 8 by 20 which is 160

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Im<br> sorry if u are having trouble seeing

algol [13]

Answer:

1) 1 to 3

2) 1/3 B*H

Step-by-step explanation:

3 0

3 years ago

Is the simplified form of 2square root of 3 + 3square root of 3 rational?<br> Yes No

mariarad [96]

2 sqrt3 + 3 sqrt3

= 5 sqrt3

Since this contains the irrational sqrt3 it is irrational

4 0

3 years ago

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Please help me with either one, (all both) I’ve been struggling with this

Sholpan [36]

Answer:

x = 12, x = 7

Step-by-step explanation:

The 2 legs of the triangle are congruent, both 2x + 7, then

2x + 7 + 2x + 7 + x + 11 = 85 ← equation for perimeter

5x + 25 = 85 ( subtract 25 from both sides )

5x = 60 ( divide both sides by 5 )

x = 12

-----------------------------------------------------------

Opposite sides are congruent, then

2(2x) + 2(5x + 3) = 104 ← distribute and simplify both sides

4x + 10x + 6 = 104

14x + 6 = 104 ( subtract 6 from both sides )

14x = 98 ( divide both sides by 14 )

x = 7

5 0

2 years ago

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what are the missing variables?

Julli [10]

Answer:Missing data (or missing values) is defined as the data value that is not stored for a variable in the observation of interest. The problem of missing data is relatively common in almost all research and can have a significant effect on the conclusions that can be drawn from the data [1].

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2 years ago

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8/x-5 - 9/x-4 = 5/x^2-9x+20

adelina 88 [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

_______________

Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}$

I hope this helps. =)

Tags: <em>rational equation fraction solution algebra</em>

7 0

3 years ago