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3 years ago

The sum of 4 and a number is at least 15

Mathematics

1 answer:

NeTakaya3 years ago

3 0

The answer should be 4+n (greater than or equal to symbol >_) 15

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-11.

dalvyx [7]

Answer:

A(2,3) has a distance of 2 to the y-axis

B(-3,2) has a distance of 3 to the y-axis

C(2,-3) has a distance of 2 to the y-axis

D(-3,-2) has a distance of 3 to the y-axis

Step-by-step explanation:

Distance of a point to an axis

Given a point (x,y) its rectangular coordinates are defined as the distances from the point to each axis with respect to the origin (0,0).

For example, the point (5,4) has a distance of 5 from the y-axis and a distance of 4 from the x-axis.

Generally speaking, point (x,y) has a distance |x| from the y-axis and a distance |y| from the x-axis.

The absolute value bars are used because the distance is always positive.

Apply that to the points:

A(2,3) has a distance of 2 to the y-axis

B(-3,2) has a distance of 3 to the y-axis

C(2,-3) has a distance of 2 to the y-axis

D(-3,-2) has a distance of 3 to the y-axis

8 0

2 years ago

3x+y=4 write the equation in slope intercept form

LekaFEV [45]

Answer:

y = -3x + 4

Step-by-step explanation:

sorry im late

but all you have to do is isolate the y

so to do that we have to get rid of the 3x

3x + y = 4

in order to do that we have to subtract 3x from both sides of the equal sign since it is positive and being added to the y

3x + y = 4

-3x -3x

y = -3x + 4

and now y is isolated

6 0

3 years ago

An angle measured 34 degrees less than the measure of a complementary angle. What is the measure of each angle?

Tanzania [10]

107 for the smaller angle or 73 if its two separate angles

4 0

3 years ago

Dy/dx= y^4 and y(2)= -1. Y(-1)=

cupoosta [38]

It looks like you're asked to find the value of y(-1) given its implicit derivative,

$\dfrac{dy}{dx} = y^4$

and with initial condition y(2) = -1.

The differential equation is separable:

$\dfrac{dy}{y^4} = dx$

Integrate both sides:

$\displaystyle \int \frac{dy}{y^4} = \int dx$

$-\dfrac1{3y^3} = x + C$

Solve for y :

$\dfrac1{3y^3} = -x + C$

$3y^3 = \dfrac1{-x+C} = -\dfrac1{x + C}$

$y^3 = -\dfrac1{3x+C}$

$y = -\dfrac1{\sqrt[3]{3x+C}}$

Use the initial condition to solve for C :

$y(2) = -1 \implies -1 = -\dfrac1{\sqrt[3]{3\times2+C}} \implies C = -5$

Then the particular solution to the differential equation is

$y(x) = -\dfrac1{\sqrt[3]{3x-5}}$

and so

$y(-1) = -\dfrac1{\sqrt[3]{3\times(-1)-5}} = \boxed{\dfrac12}$

6 0

2 years ago

Find the circumference given the area = 437.4 in². Use 3.14 for π as necessary.

Stells [14]

the circumference would be around74.1197 but you can round it down depending on the decimal place needed. The math 437.4/3.14= 139.2993630573248 then find the quare root of it =11.80251511574227=r r x 3.14 =37.0598974634374 x 2 = c

5 0

3 years ago

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