Answer:the answer is C
Step-by-step explanation:
Let ∠RTS=∠RST = a (say)
∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.
consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
I think it must be the right triangle so
x=height of the antenna
tan(66)=x/50
x=50*tan(66)
x=1.33 ft
->the height of the antenna = 1.33 ft
hope it is the correct answer because you didn't provided me enough information.