All categories

3 years ago

Solve for v. 4v = 676

Mathematics

2 answers:

SpyIntel [72]3 years ago

6 0

Answer:

v=169

Step-by-step explanation:

$4v=676$

Divide by 4.

$v=\frac{676}{4}$

$v=169$

Mazyrski [523]3 years ago

6 0

Hello!

<h2>Answer:</h2>

v = 169

<h2>Explanation:</h2>

Since it is being multiplied (4v), we're going to have to use the opposite operation to solve. The opposite of multiplication is division.

Divide both sides of the equation by 4:

$\frac{4v}{4}$ = $\frac{676}{4}$

v = 169

You might be interested in

After 5 minutes of a basketball game

astra-53 [7]

Answer:

Something happens...

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

An experiment to investigate the survival time in hours of an electronic component consists of placing the parts in a test cell

mixer [17]

Answer:

a) The sample mean is of 49 and the sample standard deviation is of 11.7.

b) The range of the true mean at 90% confidence level is of 9.62 hours.

c) The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

Step-by-step explanation:

Question a:

Sample mean:

$\overline{x} = \frac{34+40+46+49+61+64}{6} = 49$

Sample standard deviation:

$s = sqrt{\frac{(34-49)^2+(40-49)^2+(46-49)^2+(49-49)^2+(61-49)^2+(64-49)^2}{5}} = 11.7$

The sample mean is of 49 and the sample standard deviation is of 11.7.

b)Determine the range of the true mean at 90% confidence level.

We have to find the margin of error of the confidence interval. Since we have the standard deviation for the sample, the t-distribution is used.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.95$ . So we have T = 2.0.150

The margin of error is:

$M = T\frac{s}{\sqrt{n}}$

In which s is the standard deviation of the sample and n is the size of the sample. So

$M = 2.0150\frac{11.7}{\sqrt{6}} = 9.62$

The range of the true mean at 90% confidence level is of 9.62 hours.

(c)If a seventh sample is tested, what is the prediction interval (90% confidence level) of its failure time.

This is the confidence interval, so:

The lower end of the interval is the sample mean subtracted by M. So it is 49 - 9.62 = 39.38 hours.

The upper end of the interval is the sample mean added to M. So it is 49 + 9.62 = 58.62 hours.

The prediction interval, at a 90% confidence level, of it's failure time is between 39.38 hours and 58.62 hours.

4 0

2 years ago

An owner of a restraint wants to conduct a survey about possible menu changes. Give an example of a sampling method that would p

garri49 [273]

Do you mean restaraunt?

Every 10th customer
Every 15th customer

Something like that. I hope this helps.

8 0

3 years ago

Write the standard form of the equation of the line through the given points.

fenix001 [56]

You first have to find the slope using the slope formula. That looks like this with our values: $\frac{-2-(-1)}{5-(-3)}=- \frac{1}{8}$ . So the slope is -1/8. Use one of the points to first write the equation in y = mx + b form. We have an x and a y to use from one of the points and we also have the slope we just found. Filling in accordingly to solve for b gives us $-2=5(- \frac{1}{8})+b$ and $-2=- \frac{5}{8}+b$ . Adding 5/8 to both sides and getting a common denominator gives us that $b=- \frac{11}{8}$ . Writing our slope-intercept form we have $y=- \frac{1}{8}x- \frac{11}{8}$ . Standard form for a line is Ax + By = C...no fractions allowed. So let's get rid of that 8 by multiplying each term by 8 to get 8y = -x - 11. Add x to both sides to get it into the correct form: x + 8y = -11

5 0

3 years ago

Suppose a 2011 Gallup poll revealed that 76% of Americans believe that high achieving students should be recruited to become tea

k0ka [10]

Answer:

95% Confidence interval: (0.73,0.79)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 1021

Percentage of Americans believe that high achieving students should be recruited to become teachers

$\hat{p} = 76\% = 0.76$