All categories

3 years ago

What part of a pictograph tells what each picture stands for

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

7 0

The key on a pictograph tells what each picture stands for.

You might be interested in

The sum of two numbers is -10.5.

grandymaker [24]

Answer:

-5 and -5.5;

-12.5 and 2

Step-by-step explanation:

Two negative addends, can be added together to give -10.5.

For example:

(-5) + (-5.5) = -5 - 5.5 = -10.5

Also, it is possible for one of the addends to be negative while the other is positive, and their sum will give us -10.5.

For example:

The sum of -12.5 and 2 will give us -10.5.

We are adding a positive and a negative number here. As usual, we will subtract the smaller number from the bigger number, while the result will carry the sign of the bigger number, which in this case is negative sign.

Thus:

(-12.5) + (2) = -10.5

4 0

3 years ago

Someone please help me I don’t understand this

Alla [95]

Answer:

huh

Step-by-step explanation:

8 0

1 year ago

Which relation is not a function?

Lelu [443]

The Answer is A.

Repeating number is not a function. It's ok to have repeating number in Y or the range but not the X which is the Domain.

4 0

2 years ago

The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.

VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

$\int\limits^2_{-1} {(f(x) - g(x))} \, dx$

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx$

We know that:

$\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}$

$\int\limits^{}_{} {1} \, dx = x$

$\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}$

Then our integral is:

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2} + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3} + (-1) - \frac{(-1)^2}{2} )$

The right side is equal to:

$(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6$

The bounded area is 5 + 5/6 square units.

3 0

2 years ago

Find the x-intercept and the y-intercept of 2x + 6y =24

viktelen [127]

Answer:

x-intercept = 12, y-intercept = 4

Step-by-step explanation:

To find the x and y intercept, substitute 0 in for both values.

Substitute 0 into x:

2(0) + 6y = 24

6y = 24

Divide each side by 6:

y = 4

Substitute 0 into y:

2x + 6(0) = 24

2x = 24

Divide each side by 2:

x = 12

4 0

2 years ago