Answer:
f'(x) > 0 on 
and f'(x)<0 on
Step-by-step explanation:
1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:
To find its decreasing interval :
2) Then let's find the critical point of this function:
![f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Cfrac%7B%5Cmathrm%7Bd%7D%20%7D%7B%5Cmathrm%7Bd%7D%20x%7D%5B6-2%5E%7B2x%7D%5D%3D%5Cfrac%7B%5Cmathrm%7Bd%7D%20%7D%7B%5Cmathrm%7Bd%7Dx%7D%5B6%5D-%5Cfrac%7B%5Cmathrm%7Bd%7D%7D%7B%5Cmathrm%7Bd%7Dx%7D%5B2%5E%7B2x%7D%5D%3D0-%5Bln%282%29%2A2%5E%7B2x%7D%2A%5Cfrac%7B%5Cmathrm%7Bd%7D%7D%7B%5Cmathrm%7Bd%7Dx%7D%5B2x%5D%3D-ln%282%29%2A2%5E%7B2x%7D%2A2%3D-ln2%2A2%5E%7B2x%2B1%5CRightarrow%20%7Df%27%28x%29%3D-ln%282%29%2A2%5E%7B2x%7D%2A2%5C%5C-ln%282%29%2A2%5E%7B2x%2B1%7D%3D-2x%5E%7B2x%7D%28ln%28x%29%2B1%29%3D0)
2.2 Solving for x this equation, this will lead us to one critical point since x' is not defined for Real set, and x''
≈0.37 for e≈2.72
3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.
Answer:
Lines c and b, f and d (option b)
Step-by-step explanation:
To prove whether the lines satisfy the condition of being a transversal to another, let's prove one of the conditions wrong, and thus the answer -
Option 1:
Here lines a and b do not correspond to one another provided they are both transversals, thus don't act as transversals to one another, they simply intersect at a given point.
Option 2:
All conditions are met, lines c and b correspond with one another such that b is a transversal to both c and d. Lines f and d correspond with one another such that f is a transversal to both d and c.
Option 3:
Lines c and d are both not transversals, thus clearly don't act as transversals to one another.
Option 4:
Lines c and d are both not transversals, thus clearly don't act as transversals to one another.
937-837= ?
937-837=100
Hope i Helped:)
3.2 is the Length of y 7.5 is the length of z and the length of x is 12.5
Answer:
4 × ( 9 + 2z)
Step-by-step explanation:
36 + 8z = 4 × (9) + 4 × (2z) ; so here 4 is a common factor
= 4 × ( 9 + 2z)
we can also write it like this
36 + 8z = 2 × ( 18 + 4z)
