So... hmmm if you check the first picture below, for 2)
we could use the proportions of those small, medium and large similar triangles like
now.. for 3) will be the second picture below
It is the appearance of two full moons in a calendar month.
Answer:
Yes, 8 is a solution.
Step-by-step explanation:
![LHS=\frac{1}{2}x+9\\\\=[\frac{1}{2}*8]+9\\\\=4+9\\\\=13=RHS](https://tex.z-dn.net/?f=LHS%3D%5Cfrac%7B1%7D%7B2%7Dx%2B9%5C%5C%5C%5C%3D%5B%5Cfrac%7B1%7D%7B2%7D%2A8%5D%2B9%5C%5C%5C%5C%3D4%2B9%5C%5C%5C%5C%3D13%3DRHS)
When you are substituting x = 8, you can get the result 13. so 8 is the solution
Slope intercept form needs two things. The slope and y-intercept.
y = mx + b
m = the slope
b = y-intercept.
In this problem, we are given the slope and a point the line passes through.
m = -3/4
So far we have y = -3/4x + b
To find b, we need to plug the point into the line.
-4 is the x-coordinate, so we plug -4 into x
7 is the y-coordinate, so we plug 7 into y
7 = -3/4(-4) + b
Simplify.
7 = 3 + b
Subtract 3 from both sides.
4 = b
Our equation is: y = -3/4x + 4
