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3 years ago

The highest common factor of 10 and 18

Mathematics

1 answer:

Nataliya [291]3 years ago

7 0

Answer:

The highest common factor of 10 and 18 is 2

Step-by-step explanation:

10: 1,10,2,5

18: 1,18,2,9,3,6,

Look which is common in both of these and both of them have 2 in common.

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Surface-finish defects in a small electric appliance occur at random with a mean rate of 0.3 defects per unit. find the probabil

mario62 [17]

Answer: Probability that a randomly selected unit will contain at least two surface- finish defect is 0.04.

Step-by-step explanation:

Since we have given that

Mean rate defects per unit = 0.3

Since we will use "Poisson distribution":

$P(X=K)=\frac{e^{-\lambda}\lambda^k}{k!}$

But we need to find the probability that a randomly selected unit will contain at least two surface-finish defect.

$P(X\geq 2)=1+P(X=0)+P(X=1)$

So,

$P(X=0)=\frac{e^{-0.3}0.3^0}{0!}=e^{-0.3}=0.74\\\\P(X=1)=\frac{e^{-0.3}\times 0.3}{1}=0.22$

so, it becomes,

$P(X>2)=1-(0.74+0.22)=1-0.96=0.04$

Hence, probability that a randomly selected unit will contain at least two surface- finish defect is 0.04.

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4 years ago

CALLING ALL MATH GENIUS!!! Help! Please!

IrinaK [193]

2) 7/8+1/3+1/2= $1\frac{17}{24}$ , so your answer is A

3) 1/9+1/12, it's LCD (lest common denominator) is 36, $\frac{1*4}{9*4} + \frac{1*3}{12*3} = \frac{4}{36} + \frac{3}{36} = \frac{4+3}{36} = \frac{7}{36}$ so your answer is also A

4) $13+\frac{1}{4} +\frac{2}{3}$ find the Least Common Multiple (LCM) of

4, and 3, which is 12. Now make the denominators the same as the LCD, $13+\frac{1*3}{4*3} +\frac{2*4}{3*4}$ . Now Simplify; $13+\frac{3}{12} +\frac{8}{12} =13+\frac{3+8}{12} =13\frac{11}{12}$ , D is your answer.

5) LCD=9, so make the denominators the same as the LCD, $\frac{4}{9} - \frac{1*3}{3*3} = \frac{4}{9} - \frac{3}{9} = \frac{4-3}{9} =\frac{1}{9}$ . Your answer is B.

6) $30-22\frac{5}{6}, (use.the.rule...a\frac{b}{c}=\frac{ac+b}{c}...because.22\frac{5}{6}.is.an.improper.fraction)$

$30-\frac{22*6+5}{6} =30-\frac{132+5}{6}=30-\frac{137}{6} =$ make the denominators the same $30*\frac{6}{6} -\frac{137}{6} =\frac{180}{6} -\frac{137}{6} =\frac{43}{6} =7\frac{1}{6}$

7) $9\frac{5}{12}$ is an improper fraction, so you the previous rule I said to use for improper fractions.

$\frac{9*12+5}{12} -4\frac{2}{3} =\frac{108+5}{12}-4\frac{2}{3}$ , also $4\frac{2}{3}$ is an improper fraction so use the rule again.

$\frac{113}{12} -\frac{12+2}{3} =\frac{113}{12} -\frac{14}{3}$ , LCD=12

Make the denominators the same $\frac{113}{12}-\frac{14*4}{3*4}=\frac{113}{12}-\frac{56}{12} =\frac{113-56}{12} =\frac{57}{12}=\frac{19}{4}=4\frac{3}{4}$ , the answer is D

8) $21\frac{7}{9}$ , improper fraction

$\frac{21+19+7}{19} -6\frac{8}{19} =\frac{399+7}{19} -6\frac{8}{19} = \frac{406}{19} -6\frac{8}{19}$

$6\frac{8}{19}$ is an improper faction

$\frac{406}{19}-\frac{6*19+8}{19} =\frac{406}{19} -\frac{114+8}{19} =\frac{406}{19} -\frac{122}{19} =\frac{406-122}{19}=\frac{284}{19}=14\frac{18}{19}$ , the answer is B.

9) $\frac{8}{9} -\frac{6}{9} =\frac{2}{9}$ , You're trying to see how much farther he ran on Monday compared to Wednesday, so Monday goes first.

10) $\frac{3}{4} -\frac{1}{8} =\frac{5}{8}$ , You're trying to see how much more you need, so you need to subtract 1/8 (what you already have) and 3/4 to see how much you need left.

11) You're tyring to see how much she need all together, so you're looking for the sum, which is $12\frac{3}{8}$ , so the answer is C.

12) You're seeing how much he grew over the past years, so you'll be looking for the sum (addition) $1\frac{3}{4}+ 2\frac{2}{3} =4\frac{5}{12}$

19) In this problen, Claude used some of his ribbon, which in turn decreased the amount he has left, so you are looking for the difference (In this case, what he has now, vs what he originally had.) $5\frac{1}{2} -4\frac{2}{3}= \frac{5}{6}$ , your answer is C.

20) Find the time it takes in all the routes by subtracting the time you leave to the time you get there, the answer is route four because it is 2 hours and 5 minutes.

Hope this helps, have a BLESSED and wonderful day, as well as a safe one!

-Cutiepatutie ☺❀❤

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3 years ago

Need Answer Fast). The solution to a problem is an irrational number. which statement is true about the solution? Will Mark Bra

babymother [125]

Step-by-step explanation:

There is no option to choose from, but the knowledge of what irrational numbers are, would help cover this cost.

A rational number is a number that can be written as a simple fraction, a/b. Examples are 1/2, 5/6,...

If a number cannot be written as a simple fraction, then it is called irrational.

Example of irrational numbers: √2, π

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