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2 years ago

HELP ASAP!!!!!!!!! Please answer both

Mathematics

1 answer:

maks197457 [2]2 years ago

3 0

Step-by-step explanation:

questions 8, obviously the mid part of the parabola is 3, that is the axis of symmetry.

question 9, only one solution because you only have one parabola.

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Simplify the expression (9 + 2i)(9 − 2i). 81 − 18i 81 + 18i 77 85

Ymorist [56]

Answer:

=85

Step-by-step explanation:

I'm pretty sure I'm correct

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3 years ago

Y varies inversely with x.

djyliett [7]

Y is 7.5
A easy way to do it is simply graph it or divide it!
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2 years ago

Add 2 to both sides of the equation.

qwelly [4]

Answer:

See below.

Step-by-step explanation:

Adding 2 to both sides will not help solve the equation.

Adding 2 to both sides gives you this:

x^3 = ∛(x-2)

x^3 + 2 =∛(x-2) + 2

What was the original question?

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2 years ago

A sawmill runs for three 4-hour shifts per day. It produces 500 2x4's per hour, which are divided into 50 piece bundles automati

Galina-37 [17]

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3 years ago

Read 2 more answers

Determine whether the given set, together with the specified operations of addition and scalar multiplication, is a vector space

oksano4ka [1.4K]

Answer:

The set $R^2$ with x ≤ 0 and y ≤ 0 is not a vector space.
The 10th axiom $cv \in V$ does not hold

Step-by-step explanation:

Let u, v and w be vectors in the vector space V, and let c and d be scalars. A set S is defined as a vector space if it satisfies the following conditions:

1. $u+v \in V$
2. v + w = w + v
3. (u + v) + w = u + (v + w)
4. v + 0 = v = 0 + v
5. v + (−v) = 0
6. 1v = v

7. c(dv) = (cd)v

8. c(v + w) = cv + cw
9. (c + d)v = cv + dv

10. $cv \in V$

Given the set of all vectors x, y in $R^2$ with x ≤ 0 and y ≤ 0

If the scalar c is such that $c0$ .

Therefore, the 10th axiom is not satisfied and thus the set $R^2$ with x ≤ 0 and y ≤ 0 is not a vector space.

6 0

3 years ago