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arlik [135]
3 years ago
5

You are having a wedding anniversary party. In attendance are a grandfather, a grandmother, two fathers, two mothers, four child

ren, three grandchildren, one brother, two sisters, two sons, two daughters, one father-in-law, one mother-in-law and one daughter-in-law. If every person is eating two burgers, what’s the minimum amount of burgers you will need?
Mathematics
1 answer:
Alborosie3 years ago
3 0
Ok I just got the answer from Apexcode1 so I say it's 14
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A box of cereal weighs 600 grams how much is this weight in pounds
nlexa [21]

Answer:

Weight of cereal in box in pound is 1.32277 pound

Given that;

Weight of cereal in box = 600 grams

Find:

Weight of cereal in box in pound

Computation:

1 gram = 0.00220462 pound

So,

600 gram = 600 × 0.00220462 pound

600 gram = 1.32277

Weight of cereal in box in pound = 1.32277 pound

Step-by-step explanation:

<h2>HOPE IT HELPS YOU</h2>
5 0
2 years ago
Read 2 more answers
If r1 , r2 , and r3 represent rotations from Dn and f 1 , f 2 , and f 3 represent reflections from Dn , determine whether r1 r2
ziro4ka [17]

Answer:

It is reflection

Step-by-step explanation:

We know these three rules:

-a rotation followed by a rotation is a rotation

-a reflection followed by a reflection is also a rotation

-a rotation folowed by a reflection is a reflection

So we have: f3r3 is f (reflection)

f2 f is r (reflection)

r3 r is r

f2 r is f

r2 f is f

r1 f is f

So,  r1r2f1r3f2f3r3 is reflection.

7 0
3 years ago
1)
zepelin [54]

Answer:

the answer is D .I think I may not be wrong

3 0
2 years ago
Find the solutions to 2x⁴-24x²+40=0 and the x-intercepts of the graph of y=2x⁴-24x²+40.
jekas [21]

Answer:

The solutions and the x-intercepts of the polynomial 2x^4-24x^2+40 are:

x=\sqrt{10},\:x=-\sqrt{10},\:x=\sqrt{2},\:x=-\sqrt{2}

Step-by-step explanation:

Given a function <em>f</em> a solution or a root of <em>f</em> is a value x_{0} at which f(x_0)=0.

An x-intercept is a point on the graph where y is zero.

To find the solutions of the polynomial and the x-intercepts 2x^4-24x^2+40 you need to:

First, we need to factor the polynomial expression

Factor the common term

{\left(2 x^{4} - 24 x^{2} + 40\right)} = {\left(2 \left(x^{4} - 12 x^{2} + 20\right)\right)}

We can treat x^{4} - 12 x^{2} + 20 as a quadratic function with respect to x^2

Let u=x^2. We can rewrite x^{4} - 12 x^{2} + 20 in terms of u as follows:

u^2-12u+20

We need to solve the quadratic equation

u^2-12u+20=0

for this we can use the Quadratic Equation Formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-12,\:c=20:\quad u_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:20}}{2\cdot \:1}

u_1=\frac{-\left(-12\right)+\sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:20}}{2\cdot \:1}\\u_1=10

u_2=\frac{-\left(-12\right)-\sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:20}}{2\cdot \:1}\\u_2=2

the solutions to the quadratic equation are:

u=10,\:u=2

Therefore, u^2-12u+20=(u-10)(u-2)

Recall that u=x^2 so

2 x^{4} - 24 x^{2} + 40=2 \left(x^{2} - 10\right) \left(x^{2} - 2\right)=0

Using the Zero factor Theorem: If ab = 0, then either a = 0 or b = 0, or both a and b are 0.

x^2-10=0 roots are x_1=\sqrt{10}; x_2=-\sqrt{10}

x^{2} - 2=0 roots are x_1=\sqrt{2}; x_2=-\sqrt{2}

The solutions and the x-intercepts are:

x=\sqrt{10},\:x=-\sqrt{10},\:x=\sqrt{2},\:x=-\sqrt{2}

Because all roots are real roots the x-intercepts and the solutions are equal.

7 0
3 years ago
What is the answer to this question 15-6*b+6=36
sergey [27]

Answer: Im sure the answer is b= -5/2

Step-by-step explanation: Decimal form: b= -2.5

Mixed number form is: b= -2 1/2

Ikr schools just the worst- ;-;

Anywayz i hope this helps :D

5 0
2 years ago
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