37x + 45y = 7940
75x + 45y = 10,410
Since 45y is in both equations we can more easily transfer from first equation to 2nd equation.
In the first equation, subtract 37x from each side and you have 45y = 7940 - 37x. Replace the 45y in the second equation with (7940 - 37x).
Now you have 75x + (7940 - 37x) = 10,410
Simplify by combining 75x - 37x and you have 38x + 7940 = 10,410
Subtract 7940 from both sides and you have 38x = 2470.
Divide both sides by 38 and you have x = 65
To solve for y, take you first equation (or even the second one) and substitute c for 65.
(37 x 65) + 45y = 7940
2405 + 45y = 7940
Subtract 2405 from each side.
45y = 5535
Divide each side by 45 and you have y = 123
Regular tickets = $65
VIP tickets = $123
Answer:
Cole has 15 pencils.
Step-by-step explanation:
First, we have the equation c + o =18, c representing cole, and o representing connor.
From there, we get 5o=c
Using substitiution, we get o=3
5(3)=15
15+3=18
Answer:
₹66,000
Step-by-step explanation:
If 5/6 is 55,000 then just multiply 55,000 by the reciprocal 6/5 to get 66,000
Answer: i love brinly its the best
the value of x is 4, make m||n
Step-by-step explanation:
sorry if this is wrong
PART A:
The given quadratic equation is 2x²-10x-8=0
The radicand is given by b²-4ac where a, b, and c are the constants in a quadratic form ax²+bx+c
From the given equation, we have
a = 2
b = -10
c = -8
Radicand b²-4ac = (-10)² - 4(2)(-8) = 100 + 64 = 164
The radicand is >0 hence the quadratic equation has two distinct roots
PART B:
4x²-12x+5 = 0
We can use the factorization method to solve the equation
Firstly, we multiply 4 by 5 to get 20
Then we find the pair of numbers that multiply gives 20 and sum gives -12
The pair of number is -2 and -10
Rewriting the equation
4x²-2x-10x+5 = 0
2x(2x-1)-5(2x-1) = 0
(2x-1)(2x-5) = 0
2x-1 = 0 and 2x-5 = 0
x = 1/2 and x = 5/2