The price of the burritos and tacos, using the system of linear equations, is equal to $32 and $26, respectively.
It is given that for a recent company party, Carmen spent $58 on one plate of burritos and one plate of tacos. For a company meeting, she spent $90 on two plates of burritos and one plate of tacos. We need to find the cost of each dish.
Let the costs of burritos and tacos be represented by the variables "x" and "y", respectively. We can write two equations, as given below.
x + y = 58
2x + y = 90
We will substitute the value of "y" from the first equation into the second equation.
y = 58 - x
2x + y = 90
2x + 58 - x = 90
x = 90 - 58
x = 32
Hence, the price of the burritos is $32. Now, we will substitute this value into the first equation.
y = 58 - x
y = 58 - 32
y = 26
Hence, the price of the tacos is $26.
The complete question is given below.
Carmen often orders fiesta trays from her favorite Mexican restaurant for company events. For a recent company party, she spent $58 on 1 plate of burritos and 1 plate of tacos. For a company meeting, she spent $90 on 2 plates of burritos and 1 plate of tacos. How much does each type of dish cost?
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B/h=3/8
8b=3h
8/3b=h
P=2(h+b)
P=138.6
138.6=2(h+b)
divide both sides by 2
69.3=h+b
suub (8/3)b for h
69.3=(8/3)b+b
times both sides by 3 to get rid of fraction
207.9=8b+3b
207.9=11b
divide both sides by 11
18.9=b
sub back
(8/3)b=h
(8/3)18.9=h
50.4=h
area=height times base
aera=50.4 times 18.9
aera=952.56 cm²
1. base=18.9 cm
2. height=50.4 cm
3. area=952.56 cm²
Answer:
either (-1,-1) or (-4,-4)
Step-by-step explanation:
Answer:
to raise capital
Step-by-step explanation:
Test them
(x,y)
(2,4) and (3,3)
see if get true
(2,4)
-3(2)+5(4)=2(2)+3(4)
-6+20=4+12
14=16
false
(3,3)
-3(3)+5(3)=2(3)+3(3)
-9+15=6+9
6=15
false
neither
